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Montano1993 [528]
3 years ago
15

PLz, help I really don't understand these problems at all. Click here to see the screenshot

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

1. $65,000

2. A 4 and 2 mile hike

3. B 4.00

4. C multiplication

Step-by-step explanation:

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Rewrite these in increasing order of length:<br> 133 dm. 433 cm, 308 km, 91 mm
Oksi-84 [34.3K]

\boxed{91mm

<h2>Explanation:</h2>

First of all, let's transform each measurement into meter knowing the following relationships:

1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m

Therefore, we can compute the following:

\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m

Writing this in increasing order:

0.091m

<h2>Learn more:</h2>

jovian planets in order of increasing distance from the Sun: brainly.com/question/12534549

#LearnWithBrainly

7 0
3 years ago
Show different ways you can make 7502
Bingel [31]
3,751+3,751= 7,502
3,75l*2=7,502
15,004/2= 7,502
5,689+1,831=7,502
8,965-1,463=7,502
62*121=7,502
31*242=7,502
11*682=7,502
7,000+502=7,502
7,000+400+102=7,502
6,000+1,500+2



6 0
3 years ago
Tiffany has $54. She is shopping for umbrellas that cost $12 each. She writes the following equation to model the situation. Pla
neonofarm [45]

Answer:

4 umbrellas

Step-by-step explanation:

Number of Umbrellas              Total Money

                1                                            $12                

                2                                           $24

                3                                           $36

                4                                           $48

She can't go over $48 because $48 + $12 is $60, which is more than she has ($54). So the max amount of umbrellas she can buy is 4.

3 0
3 years ago
Which choice is a factor of 12
Nat2105 [25]

1, 2, 3, 4, 6, 12

All the factors of 12

8 0
3 years ago
Read 2 more answers
If b^2 - 4ac &lt; 0, then the roots of the equation ax^2 +bx +c =0 must be?
salantis [7]
Complex numbers.

b^2-4ac no solutions in real numbers.
8 0
3 years ago
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