4x³=756
x³=189
x=3 ³√7 should be acceptable
☺☺☺☺
Area of ABC : AB*AC/2
the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)
C is the second root (x-intersect), which we can find :
determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=
Hence the area of the triangle is
hence
.
We remark that
Hence 4+C=16 thus
C=12
Answer:
17.01
Step-by-step explanation:
you do subvert them so you get 17.01
Answer:
Step-by-step explanation:
Option A. All the real values of x where x < -1
Procedure
Solve the inequality:
(x -3)(x+1)>0
That happens in two cases.
1) When both factors >0
x-3>0 and x+1>0
x>3 and x >-1
The intersection is x >3
2) When both factors <0
x-3<0 and x+1<0
x<3 and x<-1
the intersection is x<-1.
We have obtained that the function is positive for the intervals x < -1 and x > 3. But in one of those intervals the function is decresing and in the other is increasing.
You can recognize that the function given is a parabola and, because the coefficient of the quadratic term is positive, the parabola opens upward. Then the function is decreasing in the first interval and increasing in the second interval.
Answer:
y = x - 2 could not be the function equation.
Step-by-step explanation:
The function with an input of 3 has an output of 5.
So, y = 2x - 1 can be the function as y(3) = 2 × 3 - 1 = 6 - 1 = 5.
Now, y = x + 2 can also be the function as y(3) = 3 + 2 = 5
Again, y = 3x - 4 can also be the function as y(3) = 3 × 3 - 4 = 9 - 4 = 5
But y = x - 2 can not be the function as y(3) = 3 - 2 = 1 ≠ 5
Therefore, y = x - 2 could not be the function equation. (Answer)
