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3 years ago

The domain of y=log(9-x^2),xER, is

Mathematics

1 answer:

jasenka [17]3 years ago

3 0

Step-by-step explanation:

log(z) is defined when z > 0.

For log(9 - x²) to be defined, we have 9 - x² > 0.

=> x² < 9, -3 < x < 3.

The domain of y = log(9 - x²) is (-3,3).

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3 years ago

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3 years ago

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Answer:

See attachment for plot

Step-by-step explanation:

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The plot at 1 and 2 minutes

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3 years ago

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Answer:

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Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

$\frac{BK}{CK} =\frac{1}{4}$

And AK meets BC at E

now in Δ AKD and Δ BKE

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since BC ║ AD and BD is transversal

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