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S_A_V [24]
4 years ago
11

How many terms are in the simplified expression 2x^2-y^2+5xy-2y

Mathematics
1 answer:
madam [21]4 years ago
7 0
6x * 3y * 9x^2y^4 <span>Simplifying 6x * 3y * 9x2y4 Reorder the terms for easier multiplication: 6 * 3 * 9x * y * x2y4 Multiply 6 * 3 18 * 9x * y * x2y4 Multiply 18 * 9 162x * y * x2y4 Multiply x * y 162xy * x2y4 Multiply xy * x2y4 162x3y<span>5</span></span>
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Decrease £16870 by 3% Give your answer rounded to 2 Decimal places​ please hurry im in a rush!!
Arturiano [62]

Answer:

$16,363.9

Step-by-step explanation:

16870 x 0.03 = 506.1

16870 - 506.1 =

8 0
3 years ago
ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.
ivann1987 [24]

Answer:

C

Step-by-step explanation:

y=\frac{1}{x-m} +b  where - m is the distance moved to the right and + b is the distance moved up. So, your solution is  y=\frac{1}{x+2}+2

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3 years ago
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3 years ago
HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x
Anna35 [415]

 

\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0


\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}




3 0
4 years ago
Decide if the following biconditional statement is true or false:
ozzi

Answer:

False

Step-by-step explanation:

I know what I talking about and I'm right

4 0
3 years ago
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