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Ganezh [65]
2 years ago
15

I can't solve number 12. If you solve the others, much appreciated.

Mathematics
1 answer:
saul85 [17]2 years ago
5 0
Answer is 18 due to the theory cause
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Which place is the 7 in? 502.78 tens tenths ones hundredths
Marina CMI [18]

Answer:

tenths

Step-by-step explanation:

Suppose a number is given in the form ABC.ZYX

The place values would be:

C is ones

B is tens

A is hundreds

Z is tenths

Y is hundredths

X is thousandths

Looking at the number 502.78, we see that "7" is the first right place after decimal, which is same as "Z", which is tenths.

Hence 7's place value is tenths

4 0
3 years ago
Read 2 more answers
Evaluate if a = 28 and b = -3.<br> a<br> 4 + b<br> = [?]
SVEN [57.7K]

Answer:

109

Step-by-step explanation:

(4)28+(-3)

4*28=112

112+(-3)

112-3

109

Hope this helps, LMK if its right

4 0
2 years ago
June needs 45 gallons of punch for a party and has 2 different coolers to carry it in. The bigger cooler is 5 times as large as
mixer [17]

Answer:

The capacity of smaller cooler = 7.5 gallons

The capacity of bigger cooler = 37.5 gallons

Step-by-step explanation:

Let smaller cooler's capacity be x gallons

Hence

Larger cooler's capacity will be 5x gallons

Together, they will hold 45 gallons, thus we can write:

x + 5x = 45

Solving:

x + 5x = 45

6x = 45

x = 45/6 = 7.5

And 5x = 5(7.5) = 37.5

The capacity of smaller cooler = 7.5 gallons

The capacity of bigger cooler = 37.5 gallons

4 0
3 years ago
{c(1) = 3/16<br> {c(n)=c(n−1)⋅4<br> ​ <br><br> what is the 3rd term in this sequence?
mote1985 [20]

Answer:

\large\boxed{c(3)=3}

Step-by-step explanation:

\left\{\begin{array}{ccc}c(1)=\dfrac{3}{16}\\\\c(n)=c(n-1)\cdot 4\end{array}\right

Put n = 2 and next n = 3 to the recursive formula:

c(2)=c(2-1)\cdot4=c(1)\cdot4\to c(2)=\dfrac{3}{16}\cdot4=\dfrac{3}{4}\\\\c(3)=c(3-1)\cdot4=c(2)\cdot4\to c(3)=\dfrac{3}{4}\cdot4=3

4 0
3 years ago
What is the completely factored form of the following expression<br> 6b2+5b-4
nlexa [21]
The answer is (2b+1)(3b-4)
3 0
3 years ago
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