twice the number is multiplying
so it would be 2c then add 4 more
so 2c+4 is the correct equation.
Answer is B
Answer:
<em>The sum of 4 consecutive odd number is 80</em>
<em>Let X be the first of these numbers</em>
<em>Then the next odd number is X+2</em>
<em>The third is X+4The fourth is X+6</em>
<em>All of these add up to 80</em>
<em>(X) + (X+2) + (X+4) + (X+6) = 80</em>
<em>Using the commutative and associative laws, let's transform this equation into</em>
<em>(X + X + X + X) + (2 + 4 + 6) = 804X + 12 = 80</em>
<em>Subtract 12 from both sides of the equation gives4X = 68</em>
<em>Divide both sides by 4 gives</em>
<em>X = 17</em>
<em>Going back to the original question:What are the 4 consecutive odd numbers: 17, 19, 21, 23Checking our answer:17 + 19 + 21 + 23 = 80 Correct!</em>
Answer:
a. H0:μ1≥μ2
Ha:μ1<μ2
b. t=-3.076
c. Rejection region=[tcalculated<−1.717]
Reject H0
Step-by-step explanation:
a)
As the score for group 1 is lower than group 2,
Null hypothesis: H0:μ1≥μ2
Alternative hypothesis: H1:μ1<μ2
b) t test statistic for equal variances
t=(xbar1-xbar2)-(μ1-μ2)/sqrt[{1/n1+1/n2}*{((n1-1)s1²+(n2-1)s2²)/n1+n2-2}
t=63.3-70.2/sqrt[{1/11+1/13}*{((11-1)3.7²+(13-1)6.6²)/11+13-2}
t=-6.9/sqrt[{0.091+0.077}{136.9+522.72/22}]
t=-3.076
c. α=0.05, df=22
t(0.05,22)=-1.717
The rejection region is t calculated<t critical value
t<-1.717
We can see that the calculated value of t-statistic falls in rejection region and so we reject the null hypothesis at 5% significance level.
Original price:
6(3.5)
21
New Price:
1.15(21)
24.15
24.15-21
$3.15 more
