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Simora [160]
3 years ago
15

Please help with this answer I don't understand it ​

Mathematics
1 answer:
USPshnik [31]3 years ago
6 0

Answer:

Step-by-step explanation:

the 1st one is 1735

The 2nd one is 1573

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Please help. I think its B since the y-intercept is -1 and it rises up 3 and goes over 1 so that means it is just 3.
borishaifa [10]
You are correct about the y-intercept. In case you are unsure about the slope, you can check using y1 - y2 / x1 - x2:

(0, -1) and (1, 2)

-1 - 2 / 0 - 1
-3 / -1
3

The slope is 3; you chose the correct answer, great job.
8 0
3 years ago
Help ASAP Please with this math problem. Just look at the picture. ​
kondaur [170]

{( \sqrt{9)} }^{2}

={3}^{2}

= 9

{9}^ \frac{1}{2}

= ({3}^{2} ) ^{ \frac{1}{2} }

= 3 ^{1}

= 3

8 0
3 years ago
The equation of the line of best fit for a scatter plot is yˆ=−14x+10 where x is age in years and y is average number of hours o
son4ous [18]

Hey there!

y = -1/4x + 10

Looking for the amount of hours of sleep for an 8 year old, so x is 8.

Solve for y:

y = -1/4(8) + 10

y = -2 + 10

y = 8

The predicted number of average hours of sleep for an 8 year old is 3. 8 hours.

Hope this helps!

5 0
3 years ago
A​ true/false test has 8080 questions. Suppose a passing grade is 5252 or more correct answers. Test the claim that a student kn
Makovka662 [10]
<h2>Answer with explanation:</h2>

Let p be the proportion of the correct answers.

As per given , we have

H_0: p=0.50

H_a: p>0.50 , since the alternative hypothesis is right tailed , so the test is a one -tailed test.

If the student gets 52 answers correct out of 80.

i.e. the proportion of correct answers : \dfrac{52}{80}=0.65

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.65-0.50}{\sqrt{\dfrac{0.50(0.50)}{80}}}\approx2.68

P-value : P(z>2.68)=0.0037   [ by using p-value table for z (right-tailed)]

Since the p-value(0.0037) is less than the significance level (0.05), so we reject the null hypothesis.

Results : We have enough evidence to support the claim that a student knows more than half of the answers and is not just guessing.

8 0
4 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at y = ± five divided by six times
blagie [28]
Refer to the diagram shown below.

In the diagram, the two vertices are located at (0, a) and (0, -a).
The equation for the parabola is
\frac{y^{2}}{a^{2}} -  \frac{x^{2}}{b^{2}} =1
The asymptotes have the equations
y= \pm \frac{a}{b} x

For the given problem,
The vertices are located at (0, +/-10).
Therefore a = 10.

The asymptotes are
y = \pm  \frac{5}{6} x
Therefore
\frac{a}{b} = \frac{10}{b} = \frac{5}{6} \\\\ 5b = 60 \\\\ b =12

Answer:
The equation of the parabola is
\frac{y^{2}}{100} - \frac{x^{2}}{144} =1


8 0
3 years ago
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