A mom mixes 9 ounces of juice with 3 ounces of water. What present of the drank is juice?

Mathematics

2 answers:

lubasha [3.4K]3 years ago

6 0

Answer:

6 ounces of juice

Step-by-step explanation:

mel-nik [20]3 years ago

6 0

Answer:

12 ounces

Step-by-step explanation:

A mom mixes 9 ounces of juice with 3 ounces of water. This means that the total ounces of drink= 9+3 = 12 ounces. The percent of the drink which is juice is: Ratio of the quantity of juice to the total quantity of drink and multiplying this obtained quantity by 100.

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Simplify (x − 4)(2x2 + 3x − 5).

xeze [42]

The simplified form of given expression is $2x^3-5x^2-17x+20$

Solution:

Given that we have to simplify the expression

Given expression is:

$(x-4)(2x^2+3x-5)$

We can simplify the expression by multiplying each term in first bracket with each term term in second bracket

$\rightarrow (x-4)(2x^2+3x-5)$

$\rightarrow (x)(2x^2)+(x)(3x)+(x)(-5)-4(2x^2)-4(3x)-4(-5)$

Simplify the above expression by multiplying the numbers in each term and adding the coefficients of like variables in each term

$\rightarrow 2x^3+3x^2-5x-8x^2-12x+20$

Combine the like terms

$\rightarrow 2x^3+3x^2-8x^2-5x-12x+20$

$\rightarrow 2x^3-5x^2-17x+20$

Thus the expression is simplified

5 0

3 years ago

The useful life of a certain piece of equipment is determined by the following formula: u=(8d)/h^2, where u is the useful life o

Anni [7]

Answer:

The correct answer is E.

Step-by-step explanation:

First I look for the relationships between the coefficients. The first term corresponds to the base value.

$\frac{8*d}{h^{2}} = \frac{8}{1} * \frac{d}{h^{2} }$

The second term corresponds to the value obtained when the density of the underlying material is doubled and the daily usage of the equipment is halved.

$\frac{2*8*d}{(0,5*h)^{2}} = \frac{16*d}{0,25 * h^{2}} = \frac{16}{0,25} * \frac{d}{h^{2} }$