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liberstina [14]
2 years ago
11

HELP What is the length of FC?

Mathematics
1 answer:
Alex17521 [72]2 years ago
5 0
It’s 12.6, the top and bottom sides are parallel to each other.
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A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

4 0
3 years ago
Determine the number of Solutions for the system of equations y = 2x + 3 and y = 2x +3
vampirchik [111]

Answer:

:/

Step-by-step explanation:

:/

7 0
2 years ago
Help me please help
Iteru [2.4K]
I am not sure but i think it’s 56•
8 0
2 years ago
Help with this one plz!
Alex17521 [72]
What do you need help with?
3 0
3 years ago
Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1, show that their volumes are in
Nuetrik [128]
<h2>\large\bold{\underline{\underline{Question:-}}}</h2>

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1 show that their volumes are in the ratio 3 : 1.

<h2>\large\bold{\underline{\underline{Solution:-}}}</h2>

⇒ Ratio of heights of two cones = 1 : 3

⇒ Ratio of radius of their bases = 3 : 1

⇒ We know that V = 1/3πr²h

⇒ Ratio of their volume = V1 : V2

\underline{ \underline{ \sf{Let's \:  find  \: the  \: ratio  \: of \:  their  \: volumes:}}}

{ \implies{ \sf  {V _{1}  :  V_{2}}}}

{ \implies{ \sf{ \frac{1}{3} \pi \:  { r_{1}}^{2}  h_{1} :  \frac{1}{3}  \pi \:  { r_{2} }^{2}  h_{2}}}}

{ \implies{ \sf{ {r_{1}}^{2}  h_{1} :  { r_{2}}^{2} h_{2}}}}

{ \implies{ \sf{ \frac{ { r_{1} }^{2} }{ { r_{2} }^{2} }  :  \frac{ h_{2} }{ h_{1} } }}} \\

{ \implies{ \sf{ \frac{ {3}^{2} }{ {1}^{2} }  :  \frac{3}{1} }}} \\

{ \implies{ \sf{ \frac{9}{1} :  \frac{3}{1}  }}} \\

{ \implies{ \sf{3 : 1}}} \\

{ \therefore{ \sf{ \green{Ratio  \: of  \: their \:  volumes = 3 : 1}}}}

4 0
3 years ago
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