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erastovalidia [21]
3 years ago
13

Can someone help me with geometry ​

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0

whats the question then?

shutvik [7]3 years ago
5 0
What is the question?
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Suppose that the data for analysis includes the attributeage. Theagevalues for the datatuples are (in increasing order) 13, 15,
Bas_tet [7]

Answer:

a) \bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96

Median = 25

b) Mode = 25, 35

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

c) Midrange = \frac{70+13}{3}=41.5

d) Q_1 = \frac{20+21}{2} =20.5

Q_3 =\frac{35+35}{2}=35

e) Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

f) Figura attached.

g) When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

Step-by-step explanation:

For this case w ehave the following dataset given:

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70.

Part a

The mean is calculated with the following formula:

\bar X = \frac{\sum_{i=1}^{27} X_i }{27}= \frac{809}{27}=29.96

The median on this case since we have 27 observations and that represent an even number would be the 14 position in the dataset ordered and we got:

Median = 25

Part b

The mode is the most repeated value on the dataset on this case would be:

Mode = 25, 35

Since 25 and 35 are repeated 4 times, so then the distribution would be bimodal.

Part c

The midrange is defined as:

Midrange = \frac{Max+Min}{2}

And if we replace we got:

Midrange = \frac{70+13}{3}=41.5

Part d

For the first quartile we need to work with the first 14 observations

13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25

And the Q1 would be the average between the position 7 and 8 from these values, and we got:

Q_1 = \frac{20+21}{2} =20.5

And for the third quartile Q3 we need to use the last 14 observations:

25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70

And the Q3 would be the average between the position 7 and 8 from these values, and we got:

Q_3 =\frac{35+35}{2}=35

Part e

The five number summary for this case are:

Min = 13 , Q1 = 20.5, Median=25, Q3= 35, Max = 70

Part f

For this case we can use the following R code:

> x<-c(13, 15, 16, 16, 19, 20, 20, 21, 22, 22, 25, 25, 25, 25, 30,33, 33, 35, 35, 35, 35, 36, 40, 45, 46, 52, 70)

> boxplot(x,main="boxplot for the Data")

And the result is on the figure attached. We see that the dsitribution seems to be assymetric. Right skewed with the Median<Mean

Part g

When we use a quantile plot is because we want to show the percentage or the fraction of values below or equal to an specified value for the distribution of the data.

By the other hand the quantile-quantile plot shows the quantiles of the distribution values against other selected distribution (specified, for example the normal distribution). If the points are on a straight line we assume that the data values fit very well to the hypothetical distribution selected.

6 0
3 years ago
Samuel was riding in the back seat of the station wagon on the way home after a long and tiring day at the
Anon25 [30]

Answer:

Samuel slept for 1/4 of the distance.

Step-by-step explanation:

The information provided are:

  • Samuel fell asleep halfway home.
  • He didn't wake up until he still had half as far to go as he had already
  • gone while asleep.

Consider that the total distance covered was 1.

Then from the first point we know that Samuel fell asleep after covering a distance of 1/2.

It is provided that he woke up only after covering half of the remaining distance.

That is, he slept for 1/4 of the remaining distance.

Thus, Samuel was asleep for 1/4th of the entire trip home.

6 0
2 years ago
If i only have 1/3 cups how many 1/3cups do i need to make a cup? answer asap!?​
Mrac [35]

Answer:

2 1/3 ssssssssssssddddss

6 0
3 years ago
Read 2 more answers
A cable installer charges $40.00 per hour plus a $60.00 service charge. Your father's firm hires him to hook up his company's in
balandron [24]
Set up the equation ... 60 + 40X = total charges... where X is the number of hours (8.5)

60 + 40(8.5) = ?
60 + 340 = ?
400 = total charges
7 0
2 years ago
Read 2 more answers
Helpp me pleasee ╹◡╹
anyanavicka [17]

Answer:

55 for 1 min

110 for 2 min

165 for 3 min

4 0
2 years ago
Read 2 more answers
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