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3 years ago

13

Can someone pls help me will give BRAINLY if correct plz help ASAP

1 answer:

sergeinik [125]3 years ago

6 0

Answer:

The prices increased from $220,000 to $245,000. Then I don't know the percentage.

Step-by-step explanation:

Ok, when you look at the prices, you see how there are lines in between, each like represents $5,000. So look at $210,000 to $230,000 each line would be starting at $210,000-$215,000-$220,000-$225,000-$230,000. So if you go to the point In-between $210,000 and $230,000, go straight down indicating that it is 2004. So when it says From 2004 to 2007, you have to put the prices as the answer for each of those two years.

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I need help<br><br> (No link please)

umka21 [38]

Answer:

the formula for finding the perimeter of a rectangle is P=2L+2W

an example of how to find the perimeter is

Explanation:

For a rectangle, its perimeter is the sum of all for sides.

The rectangle has a perimeter of 54. Find the lengths of the unknown side. That is, find S.

54=20+20+S+S

Simplify

54=40+2S

Solve for S

14=2S

S=7

Step-by-step explanation:

6 0

2 years ago

Travel A train makes a trip at 65 mi/h. A plane

Sladkaya [172]

Answer:

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Step-by-step explanation:

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8 0

2 years ago

Help me asap plz !!!!!!!!!!!!!!!!!!!

frez [133]

Answer:

The answer will be A. 27f

6 0

3 years ago

Read 2 more answers

Match the following expression 12(x-3)+18=4(2x-3) with the number of solutions below.

vfiekz [6]

12(x-3) + 18 = 4(2x-3)

12x-36+18 = 8x-12

12x -18 = 8x-12

12x-8x = -12 + 18

4x = 6

x = 6/4 or 3/2

one solution A

4 0

3 years ago

Read 2 more answers

find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).

maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).

To find:

The component equation of the plane.

Solution:

The equation of plane is

$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$

Where, $(x_0,y_0,z_0)$ is the point on the plane and $\left< a,b,c\right>$ is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

$-2(x-(-10))+5(y-7)+1(z-5)=0$

$-2(x+10)+5y-35+z-5=0$

$-2x-20+5y-35+z-5=0$

$-2x+5y+z-60=0$

$-2x+5y+z=60$

Therefore, the equation of the plane is $-2x+5y+z=60$ .

4 0

3 years ago