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solniwko [45]
3 years ago
6

$20 iteam marked down 40%

Mathematics
1 answer:
Lana71 [14]3 years ago
5 0

Answer:

$12

Step-by-step explanation:

Multiplier=0.6

20 times 0.6 = 12

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zubka84 [21]

Answer:

Hmm

Step-by-step explanation:

8 0
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Help plsss <br> find length..
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I think it’s been awhile but just ur 140/360 then times that by pi then 2 then times r= 12.22
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The spinner shown is spun 300 times.
Ann [662]

Answer:

A) 60

B) 72/300

C) 150

Step-by-step explanation:

A) P(green) = ⅕

⅕ × 300 = 60

B) purple: 72

45+37+52+94+72 = 300

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C) 1000 × (45/300)

150

8 0
3 years ago
Need help with this problem
professor190 [17]
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3 0
3 years ago
If A is a square matrix such that A^2=2I,then A^-1=?​
Afina-wow [57]

A^2=2I

Recall that I=AA^{-1}=A^{-1}A, so

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Multiply on the right by A^{-1} and regroup terms:

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A(AA^{-1})=2A^{-1}(AA^{-1})

A=2A^{-1}

and finally solve for A^{-1}:

\boxed{A^{-1}=\dfrac12A}

3 0
3 years ago
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