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RoseWind [281]
4 years ago
11

Lola and Javier have come to different conclusions about the area of this triangle. Lola believes that the area is 20 cm.2 and J

avier believes that the area is 64 cm.2 Who is correct? Defend your answer by working out the area for this triangle and explaining your process

Mathematics
1 answer:
Luda [366]4 years ago
8 0

Answer:

Neither is correct  as the correct area of the triangle is 42\ cm^2

Step-by-step explanation:

-This is a right angle triangle whose area is calculated using the formula:

A=\frac{1}{2}bh

Where, b is the base length and h the perpendicular height.

-Given b=6 and h=14, the area is calculated as:

A=0.5bh\\\\=0.5\times 6\times 14\\\\=42\ cm^2

The calculated area of the triangle is 42\ cm^2.

Hence, neither of them is correct as both 20\ cm^2 and 64\ cm^2 are incorrect area values.

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Agata [3.3K]

Answer:

130 minutes

Step-by-step explanation:

Expression:

y = 1.80x + 30

264 = 1.80x + 30

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324/1.8 = x

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3 years ago
What are the common factors of 54 24 and 18
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Read 2 more answers
HELP PLEASE! Can you please explain so I can understand how it was completed?
nlexa [21]

Answer:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

Step-by-step explanation:

Hello!

We need to determine two pairs of polar coordinates for the point (3, -3) with 0°≤ θ < 360°.

We know that the polar coordinate system is a two-dimensional coordinate. The two dimensions are:

  • The radial coordinate which is often denoted by r.
  • The angular coordinate by θ.

So we need to find r and θ. So we know that:

r=\sqrt{x^{2}+y^{2}}       (1)

x = rcos(θ)                                   (2)

x = rsin(θ)                                    (3)

From the statement we know that (x, y) = (3, -3).

Using the equation (1) we find that:

r=\sqrt{x^{2}+y^{2}}=\sqrt{3^{2}+(-3)^{2}} = 3\sqrt{2}

Using the equations (2) and (3) we find that:

3 = rcos(θ)

-3 = rsin(θ)

Solving the system of equations:

θ= -45

Then:

r = 3\sqrt{2}[/tex]

θ= -45 or 315

Notice that  there are two feasible angles, they both have a tangent of -1. The X will take the positive value, and Y the negative one.

So, the solution is:

(3 square root of 2 , 135°), (-3 square root of 2 , 315°)

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