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3 years ago

Answer the question in the picture 50 points.

Mathematics

2 answers:

aliya0001 [1]3 years ago

7 0

Answer:

<h2>➡️Here ur Answer </h2>

<h2>Option (c) ✔️✔️</h2>

kobusy [5.1K]3 years ago

3 0

Answer:

i think c

Step-by-step explanation:

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Which numbers in Set A = {−7, −4, 2, 14, 21, 34, 42} are elements of both Set B and Set C, shown below? Set B = {even numbers} S

sweet [91]

Answer:

14, 42

Step-by-step explanation:

Set A = {−7, −4, 2, 14, 21, 34, 42}

Set B = {even numbers}

Set C = {multiples of 7}

There is only one question asked

Which numbers in Set A are elements of both Set B and Set C,

We need it to be even and a multiple of 7

14 is even and a multiple of 7 and 42 is even and a multiple of 7

5 0

4 years ago

Read 2 more answers

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

3 0

3 years ago

Read 2 more answers

Eighty-five more than the square of a number is the same as the square of the quantity that is 17 less than the number. What is

mario62 [17]

We can turn this word problem into the following equation:
x^2 + 85 = (x - 17)^2
x^2 + 85 = x^2 - 34x + 289
-85 -85
_______________________
x^2 = x^2 - 34x + 204
+34x +34x
_______________________
x^2 + 34x = x^2 + 204
-x^2 -x^2
____________________
34x = 204
Divide 34 on both sides
x = 6.
The number is 6.

5 0

3 years ago

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Irina18 [472]

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3 years ago

The number of cars (c) in a parking lot increases when the parking fee (f) decreases.

Vitek1552 [10]

The answer is c maybe?

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4 years ago