Answer:
- False
- True
-- False
-- True
-- True
Step-by-step explanation:
The points are
,
,
,
and
---- missing from the question
Given

Required
Determine if each of the points would be on 
To do this, we simply substitute the value of x and of each point in
.
(a)
In this case;
and 
becomes




<em>The point </em>
<em> won't be on the graph because the corresponding value of y for </em>
<em> is </em>
<em></em>
(b) 
In this case;


becomes





<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
(c) 
In this case:

becomes





<em>The point </em>
<em> wouldn't be on the graph because the corresponding value of y for </em>
<em> is </em>
<em></em>
(d) 
In this case;

becomes


<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
(e)
In this case:
; 
becomes




<em>The point </em>
<em> would be on the graph because the corresponding value of y for </em>
is 
Answer:
25/30 and 12/30
Step-by-step explanation:
6 and 5 have a least common multiple of 30
6*5 = 30
5/6 * 5/5 = 25/30
2/5 *6/6 = 12/30
3x - 7 + 6 = 7x + 6
First shift all the pure numbers to one side
3x = 7x + 6 + 7 - 6
Now add up the pure numbers
3x = 7x + 7
Shift the 7x to the other side
3x - 7x = 7
-4x = 7
Divide 7 by - 4
X = - 1.75