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Andreas93 [3]
4 years ago
6

What does this equal to in standard form? (A+bi)

Mathematics
2 answers:
Fudgin [204]4 years ago
5 0

Answer:

-33 - 21i

Step-by-step explanation:

3i (-7 + 11i)

= -21i + 33i^2                   (i^2 = -1)

= -21i + 33(-1)

= -33 - 21i

elena55 [62]4 years ago
3 0

3i(-7+11i)=-28i+33i^2=\boxed{-33-28i}

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Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (round your answers to the nea
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Given a table below which gives the years in A.D. for an archaeological excavation site using the method of tree ring dating:

\begin{tabular}
{|c|c|c|c|c|c|c|c|c|}
1229&1292&1187&1257&1268&1316&1275& 1317&1275
\end{tabular}

Part A:

The sample mean is given by:

\bar{x}= \frac{1229+1292+1187+1257+1268+1316+1275+ 1317+1275}{9} \\  \\  = \frac{11416}{9} =1268

Therefore, the sample mean is 1268.



Part B:

We calculate the sample standard deviation as follows:

s= \frac{1}{9-1} \left(\sqrt{(1229-1268)^2+(1292-1268)^2+(1187-1268)^2+(1257-1268)^2+(1268-1268)^2+(1316-1268)^2+(1275-1268)^2+(1317-1268)^2+(1275-1268)^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{(-39)^2+24^2+(-81)^2+(-11)^2+0^2+48^2+7^2+49^2+7^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{1521+576+6561+121+2304+49+2401+49}\right)\\ \\ = \frac{1}{8}\left(\sqrt{13,582}\right)\\ \\ = \frac{1}{8}(116.54)=14.57\approx15



Part C:

The 90% confidence interval is given by:

90\% \ C. \ I.=1268\pm1.65\left(\frac{15}{\sqrt{9}}\right) \\  \\ =1268\pm\left(\frac{15}{3}\right)=1268\pm5 \\  \\ =(1268-5, \ 1268+5)=(1263, \ 1273)
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Reflect across the y axis and moved through the translation x = 2
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Stolb23 [73]

a_n = a_ (n-1) +d



a)   2,8,14,.......

b)  8-2 =6

14-8 =6

d=6

c) a_n = a_ (n-1) +8

check:

a_1 = 2

a_2 = a_ 1  +6  = 2+6  =8

2_3   = a_2  + 6   = 8 + 6=14

a_n = a_ (n-1) +8



7 0
3 years ago
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