I’m asking for your help ASAP thank you so much if you respond.
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Answer:
<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>
Step-by-step explanation:
Probability =
We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20
<em>Total possible outcomes: 20</em>
<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>
1, 3, 5, 7, 9, 11, 13, 15, 17, 19
Probability of spinner stoping on Odd number:
P(Odd) = =
=
= 0.5
Outcomes that spinner will stop on a multiple of 5, n(5): 4
5, 10, 15, 20
Probability of spinner stoping on multiple of 5:
P(5) = =
=
= 0.2
Odd numbers which are a multiple of 5 are: 5 and 15
So,
P(Odd and 5) =
Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:
P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6
The tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.
<em>Lets simplify the problem,</em>
Let assume the "tens" digit be x
Then the "units" difference = (x-1), according to the condition.
Hence, the number itself is N = 10x + (x-1).
Then the number N+8 is 10x + (x-1) + 8 = 10x + x + 7 = 11x + 7.
From the last statement of the problem, we have this equation
Simplify and find "x"
.
Thus the tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.
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