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dangina [55]
3 years ago
13

Find the ordered pairs. {Y=(x+1)^2-5 {Y=2x PLEASE HELP!!!

Mathematics
1 answer:
vampirchik [111]3 years ago
6 0

Answer:

\large \boxed{\sf \bf \ \ \text{The solutions are }(2,4) \text{ and } (-2,-4) \ \ }

Step-by-step explanation:

Hello, this is the same kind of question that you have already posted( brainly.com/question/17141820).

<em>I would suggest that you check my previous answer and try to apply the same logic here. When you try it if you have any question please let me know. It will be the more efficient way for you to learn how to solve it by yourself.</em>

<em>As I have already provided details for the previous question I will be more succinct here.</em>

Again we can write y = y and then we have to solve the following.

(x+1)^2-5=2x\\\\x^2+2x+1^2-5-2x=0\\\\x^2-4=x^2-2^2=(x-2)(x+2)=0\\\\x=2 \ \ or \ \ x=-2

The solutions are (2,4) and (-2,-4)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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3 years ago
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The measures of 5 of the Interior angles of a hexagon are: 115.125", 85", 150", and 170". What is the measure of the
levacccp [35]

The measure of the  largest exterior angle of hexagon is 105

<u>Solution:</u>

Given, The measures of 5 of the Interior angles of a hexagon are: 115.125", 85", 150", and 170".  

We have to find what is the measure of the largest exterior angle?  

Now let us find the 6th interior angle,  

We know that, sum of interior angles of hexagon = 720 degrees

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Now we have to find the largest exterior angle, we know that, the complement of largest exterior angle will be smallest interior angle.

So, here smallest interior angle is 75  

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3 years ago
Graph and check to solve the linear system <br> x+y=3<br> -2x+y=-6
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Answer:

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Westkost [7]

Hello!

\large\boxed{x^{4}}

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\sqrt[z]{x^{y} } is equal to x^{\frac{y}{z} }.  Therefore:

\sqrt[3]{x^{2} } = x^{\frac{2}{3} }

There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

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