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3 years ago

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Jake is constructing a triangle. He drew a side length that is 8 inches long and another side length that is 13 inches long. Whi

ch of the following could be the length of the third side of Jake’s triangle, in inches?
A.5

B.13

C. 21

D. 22

1 answer:

Luba_88 [7]3 years ago

7 0

Answer:

A. 5

Step-by-step explanation:

because 13 is the hypotenuse and 8 is the sine

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Simplify sin Θ/√1-sin^2 Θ

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If you're using the app, try seeing this answer through your browser: brainly.com/question/2862279

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Simplify the trigonometric expression.

Call the expression E:

$\mathsf{E=\dfrac{sin\,\theta}{\sqrt{1-sin^2\,\theta}}\qquad\qquad(but~~1-sin^2\,\theta=cos^2\,\theta)}\\\\\\
\mathsf{E=\dfrac{sin\,\theta}{\sqrt{cos^2\,\theta}}}\\\\\\
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$\mathsf{E}=\left\{\!\begin{array}{rl}\mathsf{\dfrac{sin\,\theta}{cos\,\theta}\,,}&\mathsf{\quad if~~cos\,\theta>0}\\\\\mathsf{\dfrac{sin\,\theta}{-\,cos\,\theta}\,,}&\mathsf{\quad if~~cos\,\theta$

So basically E is equivalent to $\pm\,\mathsf{tan\,\theta},$ where the sign depends on which quadrant $\theta$ lies. Shortly,

$\mathsf{\dfrac{sin\,\theta}{\sqrt{1-sin^2\,\theta}}}=\left\{\!
\begin{array}{rl}
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I hope this helps. =)

Tags: <em>simplify trigonometric trig expression sine cosine tangent sin cos tan absolute value modulus trigonometry</em>

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Let's rewrite the given equation into the form of y=mx+c, so that we can find the gradient of the line. In this form, m (coefficient of x) is the gradient.

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<em>Divide</em><em> </em><em>by</em><em> </em><em>2</em><em> </em><em>throughout</em><em>:</em>

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