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navik [9.2K]
2 years ago
11

Tyna simplified the expression StartFraction 3 x cubed Over 12 x Superscript negative 2 Baseline EndFraction to StartFraction x

Over 4 EndFraction. What was Tyna's mistake? She divided the coefficients incorrectly. She added the exponents instead of subtracting them. She divided the coefficients instead of subtracting them. She subtracted the exponents instead of dividing them.
Mathematics
1 answer:
Yuki888 [10]2 years ago
3 0

Answer:

She divided the coefficients incorrectly

Step-by-step explanation:

A. She divided the coefficients incorrectly.

B. She added the exponents instead of subtracting them.

C. She divided the coefficients instead of subtracting them.

D. She subtracted the exponents instead of dividing them.

Correct calculation:

3x³/12x^-2

= 3x³ ÷ 12x^-2

= 3x³ ÷ 1/12x²

= 3x³ × 12x²/1

= 36x^5

Tyna's calculation:

3x³/12x^-2 = x/4

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The price p, in dollars, of a specific ca that is x year old is modeled by the function p(x)=22,255(0.91)^x
uysha [10]

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

The price p, in dollars, of a specific car that is x year old is modeled by the function p(x)=22,255(0.91)^x

a) to determine the cost of a 2 year old car, we will substitute 2 for x in the given function. Therefore

p(2)=22,255(0.91)^2

p(2)=22,255 × 0.8281 = $18673.655

Approximately $18674

b) to determine the cost of a 7 year old car, we will substitute 7 for x in the given function. Therefore

p(7)=22,255(0.91)^7

p(2)=22,255 × 0.51676101936 = 11500.51648579693

Approximately $11501

c) 0.91 indicates exponential decay rate. It is a fixed percentage by which the value of the car decreases every year. It is determined by (1 - rate of decay)

7 0
2 years ago
Melissa buys 2 1/2 pounds of salmon and 1 1/4 pounds of swordfish. She pays a total of $31.25, and the swordfish cost $.20 per p
julsineya [31]

Answer:

The combined cost of 1 pound of salmon and 1 pound of swordfish is $16.66

Step-by-step explanation:

Let us assume the cost of 1 pound salmon = $ m

So the cost of 1 pound of 1 pound swordfish cat = $ ( m - 0.20)

Now, the Amount of salmon purchased  = 2 1/2 pounds

2\frac{1}{2}  = 2 + \frac{1}{2} = 2 + 0.5 = 2.5

So, the amount of salmon purchased = 2.5 pounds

Cost of buying 2.5 pounds = 2.5 x ( 1 pound cost)

= 2.5 ( m) = $ 2.5 m  ...... (1)

Also, the Amount of swordfish purchased  = 1 1/4 pounds

1\frac{1}{4}  = 1 + \frac{1}{4} = 1 + 0.25 = 1.25

So, the amount of swordfish purchased = 1.25 pounds

Cost of buying 1.25 pounds = 1.25 x ( 1 pound cost of swordfish)

= 1.25 ( m - 0.20) = $ 1.25 m - 0.25       .... (2)

Now, the combined cost paid  = $ 31.25

⇒Cost of buying (2.5 pounds salmon  +  1.25 pounds swordfish) = $ 31.25

or, 2.5 m +   1.25 m - 0.25  = 31.35       (from (1) and (2))

or, 3.75 m = 31.60

or, m = 31.60/3.75 =  8.43

⇒ m = $8.43

So, the cost of 1 pound salmon = m = $8.43

and the cost of 1 pound swordfish = m - 0.20 = $8.43 - 0.20 = $ 8.23

Hence, the combined cost  1 pound of salmon and 1 pound of swordfish = $8.43 + $ 8.23 =  $ 16.66

6 0
3 years ago
if you put an object that has amass of 40 grams on one side of a balance scale,you would have to put about 18 U.S. dimes on the
Ne4ueva [31]
It would have to be 25 dimes
4 0
2 years ago
If f(1) = 2 and f(n) = f(n − 1)² + 4 then find the value of ƒ (3).
erma4kov [3.2K]

Answer:

f(3) = 68

Step-by-step explanation:

→ f(1) = 2 ⇒ f(2) = f²(2 − 1) + 4

                     = f²(1) + 4

                     = 2² + 4

                     = 8

………………………………………………

→ f(2) = 8 ⇒ f(3) = f²(3 − 1) + 4

                      = f²(2) + 4

                      = 8² + 4

                      = 64 + 4

                      = 68

6 0
2 years ago
Divide the sum of (-24),(-10) and (-40) by the product of (-5) and 3​
PilotLPTM [1.2K]

Answer:

4.93333...

Step-by-step explanation:

-24 + (-10) + (-40) = -74

-5 * 3 = -15

-74 /-15 = 4.93333...

5 0
3 years ago
Read 2 more answers
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