The magnitude of each vector is the Pythagorean sum of its components.
a. |v1| = √(2² + (-6)²) = √40 = 2√10
|v2| = √((-4)² + 7²) = √65
b. To make each vector into a unit vector, divide each component by the vector's magnitude.
u1 = v1/|v1| = (2/(2√10), -6/(2√10))
u1 = (√10/10, -3√10/10)
u2 = v2/|v2| = (-4/√65, 7/√65)
u2 = (-4√65/65, 7√65/65)
The total number of students is 250 from the solution in the image.
Answer:
<h2>x = 5</h2>
Step-by-step explanation:
|<------------------- 32 units ---------------->|
K-----------------------L-------------------------M
3x + 6 11
KL + LM = KM
3x + 6 + 11 = 32
3x = 32 - 11 - 6
x = 15 / 3
x = 5 units
Answer:
f(x) = -1.18056x² +9.55556x -12.4604
Step-by-step explanation:
As required by the problem statement, technology was used to find the polynomial function that passes through the given points. The coefficients shown above are rounded to 6 significant figures. The exact coefficients appear to be ...
f(x) = (-1 13/72)x² +(9 5/9)x -(12 221/480)
