The answer is the first one, impossible. This is because it shows that there are red and black cards, but never mentions that there are blue cards at all. This also means there are no blue cards. How could you get a blue card when there are none? It's impossible.
We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.
We have from day 1:
A: 3s + 9c = 75
And from day 2:
B: 8s + 5c = 67
Now we can rewrite A as:
A: 24s + 72c = 600
And can rewrite B as:
B: 24s + 15c = 201
Now A-B can be written as:
A-B: 57c = 399
So c = 7
Now substituting this back into A we get:
A: 3s + 63 = 75
A: 3s = 12
So s = 4
We have the price of a senior ticket is $4 and the price of a child ticket is $7
We can write that as a function:
where 
is the number of price reductions. We can see that it is a quadratic function which has the biggest value at P = (p, q). It means that p is the number of reductions which results in the biggest profit.
It means that it's the best to make 2 price reductions for the company. The tickets should be sold for $200 - 2 * $20 = $160. It results in 2 * 50 more tickets sold which is 300 + 100 = 400.
Answer:
Ticket price: $160
Number of tickets: 400
The answer is: 
The explanation is shown below:
1. You have the following expression given in the exercise above:
2. By applying the distributive property, you obtain:
3. Now, you must factor
in the numerator and
in the denominator:
4. Simplify:
Answer:
141.4 sq cm
Step-by-step explanation:
to find the area of the outer circle with a smaller circle inscribed within, you find the area of each and subtract the smaller area from the larger
the radius of the smaller circle is 2
we have to find the radius of the larger circle so we use what we know about its circumference:
C = 2πr
43.96 = 2πr
21.98 = πr
21.98 / π = r
r ≈ 7 cm
now use r = 7 to find area of larger circle:
A = πr²
A = π49
Area of smaller circle: 4π
Area of larger circle without including inner section is 49π - 4π = 45π
45π ≈ 141.4 sq cm
