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Gwar [14]
3 years ago
13

the radius of the inner white circle of the doughnut is 2cm. The circumference of the outer edge of the doughnut is 43.96cm. Wha

t is the area of just the brown part of the doughnut (excluding the inner white section)?
Mathematics
1 answer:
Elenna [48]3 years ago
7 0

Answer:

141.4 sq cm

Step-by-step explanation:

to find the area of the outer circle with a smaller circle inscribed within, you find the area of each and subtract the smaller area from the larger

the radius of the smaller circle is 2

we have to find the radius of the larger circle so we use what we know about its circumference:

C = 2πr

43.96 = 2πr

21.98 = πr

21.98 / π = r

r ≈ 7 cm

now use r = 7 to find area of larger circle:

A = πr²

A = π49

Area of smaller circle:  4π

Area of larger circle without including inner section is 49π - 4π = 45π

45π ≈ 141.4 sq cm

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3 years ago
In ΔSTU, the measure of ∠U=90°, the measure of ∠T=32°, and US = 5.8 feet. Find the length of ST to the nearest tenth of a foot.
murzikaleks [220]

Answer:

10.9451≈10.9 feet

Step-by-step explanation:

sinT= hypotenuse/ opposite = x/5.8

sin32= x/5.8

x*sin 32=5.8

x=5.8/sin 32= <u>10.9451≈10.9 feet</u>

8 0
2 years ago
XY is a diameter of a circle and Z is a point on the circle such that ZY=6. If the area of the triangle XYZ is 18 square root 3
nataly862011 [7]
<h2>Answer:</h2>

4π

<h2>Step-by-step explanation:</h2>

As shown in the diagram, triangle XYZ is a right triangle. Therefore, its area (A) is given by:

A = \frac{1}{2} x b x h      -------------(i)

Where;

A = 18\sqrt{3}

b = XZ = base of the triangle

h = YZ = height of the triangle = 6

<em>Substitute these values into equation(i) and solve as follows:</em>

18\sqrt{3} =  \frac{1}{2} x b x 6

18\sqrt{3} =  3b

<em>Divide through by 3</em>

6\sqrt{3} =  b

Therefore, b = XZ = 6\sqrt{3}

<em>Now, assume that the circle is centered at O;</em>

Triangle XOZ is isosceles, therefore the following are true;

(i) |OZ| = |OX|

(ii) XZO = ZXO = 30°

(iii) XOZ + XZO + ZXO = 180°   [sum of angles in a triangle]

=>  XOZ + 30° + 30° = 180°

=>  XOZ + 60° = 180°

=>  XOZ = 180° - 60°

=>  XOZ = 120°

Therefore we can calculate the radius |OZ| of the circle using sine rule as follows;

\frac{sin|XOZ|}{XZ} = \frac{sin|ZXO|}{OZ}

\frac{sin120}{6\sqrt{3} } = \frac{sin 30}{OZ}

\frac{\sqrt{3} /2}{6\sqrt{3} } = \frac{1/2}{|OZ|}

\frac{1}{12}  = \frac{1}{2|OZ|}

\frac{1}{6} = \frac{1}{|OZ|}

|OZ| = 6

The radius of the circle is therefore 6.

<em>Now, let's calculate the length of the arc XZ</em>

The length(L) of an arc is given by;

L = θ / 360 x 2 π r          ------------------(ii)

Where;

θ = angle subtended by the arc at the center.

r = radius of the circle.

In our case,

θ = ZOX = 120°

r = |OZ| = 6

Substitute these values into equation (ii) as follows;

L = 120/360 x 2π x 6

L = 4π

Therefore the length of the arc XZ is 4π

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tino4ka555 [31]

Answer:

x=3

Step-by-step explanation:

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<A = <B

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Subtract 4x from each side

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3x+2 =11

Subtract 2 from each side

3x+2-2 = 11-2

3x = 9

Divide by 3

3x/3 = 9/3

x=3

7 0
3 years ago
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