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BabaBlast [244]
2 years ago
8

Can you please help me!? ​

Biology
1 answer:
monitta2 years ago
6 0

Answer:

You need to compare the location of bands for X and X's child. X is the mother, so the child will have half of all its bands from its mother, and the other half must be from the father. Some bands that X and X's child have in common are at around 185bp and 130bp (it is difficult for me to determine the exact position). Then look at the bands which X and X's child do not have in common. Those bands must have come from the father. So now you compare the remaining bands to all the bands of Megabucks and see if they match up. You can see a band at around 60bp that the child has. The mother did not have this band, so it must have come from the father. Megabucks does not have this band, so he is not X's father.

Explanation:

I hope this has helped you a little. The main thing to know is that a child's bands come from their mother and father, so if half the bands match up to the mum, the other half have to match up to some of the father's bands. But a child will never have the same set of bands as one of their parents - it will be a mix of both parents' bands.

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write an essay about the best meal you’ve ever eaten using all five senses (smell, taste, hearing, touch, sight)
san4es73 [151]

I was sitting in my room, my eyes glued to the flashing screen, the palm of my hands slick with sweat as I struggled to hold onto the controller, the smooth surface slipping every second or so. I could barely hear anything, but the blaring of the sound effects that blasted through my room, shutting out any sound, including the knock on my door from my mother. I started, dropping the controller, my eyes wide. I snapped "What!" at my mother, her face contorting into pinched irritation. "Dinner is ready." She said, turning away to head back down the stairs. My eyes shifted to the open doorway, the nostrils of my nose flaring as I took in the scent of food. I could smell spices, and the humid stench of steam. My stomach growled and I quickly shot up from the floor and thundered down the stairs, leaping into the kitchen to find the source of the heavenly smells that wafted in my direction. I spotted turkey, garnished with lemon and green herbs, and sitting beside it, a large bowl of something off-white. It looked like mashed potatoes. I hastily took a seat and set my elbows upon the wooden surface of the table, my mother scolding me over her shoulder as she divided place settings. "Elbows off, please." She piped, pulling out her own chair with an ear splintering squeal that grated my nerves, causing my teeth to grind together. My mother passed a plate of green beans towards me, and I quickly scooped them onto my own plate, then going for the turkey, the mashed potatoes added last. With no time for prayer, I dug in, the tinges of my fork scraping against the plates clay surface as I scooped a fork full of beans up, and shoved it into my mouth. It tasted bland, with the barest hint of salt. I swallowed, cringing as it went down and took a bite of the mashed potatoes. Of course it was delicious. They were light, buttered perfectly. I gave a small sound of appreciation and went for the turkey last. I stabbed a piece of meat and popped it into my mouth, the texture odd. Hard to describe really. It was tough, but also soft enough to bite into, and with lemon added into it, it was tangy, making my mouth salivate. My mom smiled at the expression my face, nearly laughing. I made a face at her and swallowed, going in for another bite.

6 0
3 years ago
Explain how we know that DNA breaks and rejoins during recombination.
alisha [4.7K]

Answer:

It occurs through homologous recombination

Explanation:

GENERAL RECOMBINATION OR HOMOLOGIST

           Previously we defined its general characteristics. We will now describe a molecular model of this recombination, based on the classic Meselson and Radding, modified with the latest advances. Do not forget that we are facing a model, that is, a hypothetical proposal to explain a set of experimental data. Not all points of this model are fully clarified or demonstrated:

           Suppose we have an exogenote and an endogenote, both consisting of double helices. In recombination models, the exogenote is usually referred to as donor DNA, and the endogenote as recipient DNA.

1) Start of recombination: Homologous recombination begins with an endonucleotide incision in one of the donor double helix chains. Responsible for this process is the nuclease RecBCD (= nuclease V), which acts as follows: it is randomly attached to the donor's DNA, and moves along the double helix until it finds a characteristic sequence called c

Once the sequence is recognized, the RecBCD nuclease cuts to 4-6 bases to the right (3 'side) of the upper chain (as we have written above). Then, this same protein, acting now as a helicase, unrolls the cut chain, causing a zone of single-stranded DNA (c.s. DNA) to move with its 3 ’free end

2) The gap left by the displaced portion of the donor cut chain is filled by reparative DNA synthesis.

3) The displaced single chain zone of the donor DNA is coated by subunits of the RecA protein (at the rate of one RecA monomer per 5-10 bases). Thus, that simple chain adopts an extended helical configuration.

4) Assimilation or synapse: This is the key moment of action of RecA. Somehow, the DNA-bound RecA c.s. The donor facilitates the encounter of the latter with the complementary double helix part of the recipient, so that in principle a triple helix is formed. Then, with the hydrolysis of ATP, RecA facilitates that the donor chain moves to the homologous chain of the receptor, and therefore matches the complementary one of that receptor. In this process, the chain portion of the donor's homologous receptor is displaced, causing the so-called "D-structure".

It is important to highlight that this process promoted by RecA depends on the donor and the recipient having great sequence homology (from 100 to 95%), and that these homology segments are more than 100 bases in length.

Note that this synapse involves the formation of a portion of heteroduplex in the double receptor helix: there is an area where each chain comes from a DNA c.d. different parental (donor and recipient).

5) It is assumed that the newly displaced chain of the recipient DNA (D-structure) is digested by nucleases.

6) Covalent union of the ends originating in the two homologous chains. This results in a simple cross-linking whereby the two double helices are "tied." The resulting global structure is called the Holliday structure or joint.

7) Migration of the branches: a complex formed by the RuvA and RuvB proteins is attached to the crossing point of the Holliday structure, which with ATP hydrolysis achieve the displacement of the Hollyday crossing point: in this way the portion of heteroduplex in both double helices.

8) Isomerization: to easily visualize it, imagine that we rotate the two segments of one of the DNA c.d. 180o with respect to the cross-linking point, to generate a flat structure that is isomeric from the previous one ("X structure").

9) Resolution of this structure: this step is catalyzed by the RuvC protein, which cuts and splices two of the chains cross-linked at the Hollyday junction. The result of the resolution may vary depending on whether the chains that were not previously involved in the cross-linking are cut and spliced, or that they are again involved in this second cutting and sealing operation:

a) If the cuts and splices affect the DNA chains that were not previously involved in the cross-linking, the result will be two reciprocal recombinant molecules, where each of the 4 chains are recombinant (there has been an exchange of markers between donor and recipient)

b) If the cuts and splices affect the same chains that had already participated in the first cross-linking, the result will consist of two double helices that present only two portions of heteroduplex DNA.

8 0
3 years ago
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