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How Many questions do They give on The SAT

Dovator [93]

This may not be church, but I think 100

3 0

4 years ago

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State two ways in which media could ensure access of information to all communities brainly

Luba_88 [7]

The media ensure access to information because there is a wide variety of media with different opinions and collect information on different topics.

<h3>What are the media?</h3>

The media are a set of tools that have allowed the publication of information for the reader. The information used by the media is generally focused on a public and has a specific purpose to inform.

<h3>How do the media ensure access to information?</h3>

The media can assure the public access to true and reliable information because they have primary sources in different places to collect the news.

Additionally, they have developed different means of dissemination such as the internet, mobile and printed versions to have coverage over a greater number of people.

Learn more about media in: brainly.com/question/7887964

3 0

3 years ago

A study suggests that about 80\%80%80, percent of undergraduate students are working at a job. Researchers plan to do a follow-u

Leni [432]

Using the z-distribution, it is found that the smallest sample size required to obtain the desired margin of error is of 4330.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem:

The estimate of the proportion is of $\pi = 0.8$ .

The desired margin of error is of M = 0.01.

90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so $z = 1.645$ .

Then, we solve for n to find the minimum sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.645\sqrt{\frac{0.8(0.2)}{n}}$

$0.01\sqrt{n} = 1.645\sqrt{0.8(0.2)}$

$\sqrt{n} = \frac{1.645\sqrt{0.8(0.2)}}{0.01}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.8(0.2)}}{0.01}\right)^2$

$n = 4329.6$

Rounding up, the smallest sample size required to obtain the desired margin of error is of 4330.

To learn more about the z-distribution, you can take a look at brainly.com/question/12517818

7 0

2 years ago

What information is not included in a company's prospectus brainly

STALIN [3.7K]

A company's prospectus is any legal document that provides information and full details of the company.

<h3>The information in a company's prospectus</h3>

The question is incomplete, so I will list the information is a company's prospectus, instead.

The information include:

The company's management and their experience
Brief summary of the company's background
The years of company's establishment
Company name
The company's principals
etc...

Read more about company at:

brainly.com/question/24448358

6 0

3 years ago

Based on this theory, what distance will the handler move from the starting point to the return point if he creates an arc of a

dem82 [27]

Based on this theory, the distance that the handler move from the starting point to the return point if he creates an arc of a circle with radius 80 fee is 125.6 feet.

<h3>What is a distance?</h3>

This is known to be the rate or amount of space that is found between two things and others.

Note therefore, Based on this theory, the distance that the handler move from the starting point to the return point if he creates an arc of a circle with radius 80 fee is 125.6 feet.

Learn more about distance from

brainly.com/question/2854969

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4 0

2 years ago

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