Answer:
$1.25
September
$30
Step-by-step explanation:
Let's take this a step a time.
First we need to find how much the price of the flowers were in September.
We know that each flower cost $1.50 on October.
The October price was a 20% increase of the September price.
To calculate for the price of the flowers on September, we can solve it like this:
Let x = Price during September
1.2x = 1.50
We used 1.2 because the price of $1.50 is 120% of the original price.
Now we divide both sides by 1.2 to find x.
x = 1.25
The price of the flowers during September was $1.25 each.
Now the 7th grade class earned 40% of the selling price of each flower.
40% = 0.40
To find how much they made on each month, we simply multiply the percentage to the price and the number of flowers sold.
September = 0.40 x 1.25 x 900
September = 0.5 x 900
September = $450
Now for October.
October = 0.40 x 1.50 x 700
October = 0.6 x 700
October = $420
The 7th Graders earned more on September.
They earned $30 more on September than October.
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way
Step-by-step explanation:
- From a standard deck of cards, one card is drawn. What is the probability that the card is black and a
jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
- A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen
or an ace.
P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13
- WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?
P(AA) = (4/52)(3/51) = 1/221.
- WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?
P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.
- WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the
probability of drawing the first queen which is 4/52.
- The probability of drawing the second queen is also 4/52 and the third is 4/52.
- We multiply these three individual probabilities together to get P(QQQ) =
- P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
- Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
30kx - 6kx = 8
24kx = 8 /(÷8)
3kx = 1
x = 1/3k
Answer:
$3378.3
Step-by-step explanation:
P= 1500
R= 75
T= 12 years
A= P(1+R/100)^T
A= 1500(1+7/100)^12
A=1500(1.07)^12
A= $3378.3
Hoi! Its your friend Nat here to help!
All we need to do is
2.70+3.60
Which is 6.3
Hope dis helps!
<em>~</em><em>Learning</em><em> </em><em>with</em><em> </em><em>Natalia</em><em>~</em>
