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Anna [14]
3 years ago
10

Find the sum of the first 10 terms of the following geometric sequences: 3,6,12,24,48

Mathematics
1 answer:
jeka57 [31]3 years ago
4 0

Answer:

3,069

Step-by-step explanation:

The sequence is doubling, so terms 1 through 10 are:

3, 6, 12, 24, 48, 96, 192, 384, 768, 1,536

3 + 6 + 12 + 24 + 48 + 96 + 192 + 384 + 768 + 1,536 = 3,069

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The product of a number and ten is twelve more than the product of the number and five-eighths.
ra1l [238]
Let the unknown number be x.

Given,

10 * x = 12 +  \frac{5}{8}  * x

10x = 12 +  \frac{5x}{8}

10x -  \frac{5x}{8} = 12

\frac{(10x*8)-5x}{8} = 12

80x-5x =12*8

75x = 96

x = \frac{96}{75} = 1.28

Hence, the number is 1.28
3 0
3 years ago
In a choir there are 27 men and 60 women.
guapka [62]

Answer:

b) A person is chosen at random from the choir.

Work out the probability that the person.

Work out the probability that the person does not wear glasses

8 0
2 years ago
If [x] denotes the least integer greater than or equal to x and [x/2] = 0, which of the following could be the value of x?A. -2B
podryga [215]

Answer:

B) -3/2

Step-by-step explanation:

If [x/2]=0 then x/2 is a number such that the least integer greater than or equal to x/2 is 0. We can rewrite this as the inequality x/2≤0. Then, the value of x in C, D and E is wrong because they are positive numbers, then x/2 would be a positive number which contradicts this inequality.

Now, 0 is the least integer that satisfies this inequality, therefore we cannot have that x/2≤-1 since -1 is an integer and -1<0. Then x/2>-1. This discards A as wrong, because for x=-2, x/2=-1, contrary to x/2>-1.

Thus B is the right answer. To verify, if x=-3/2, then x/2=-3/4 and we have that -1<-3/4≤0 as required.

3 0
2 years ago
uppose we want to build a rectangular storage container with open top whose volume is $$ cubic meters. Assume that the cost of m
Ainat [17]

Answer:

a = length of the base = 2.172 m

b = width of the base = 1.357 m

c = height = 4.072 m

Step-by-step explanation:

Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?

lets call a = length of the base

b = width of the base

c = height

V = a.b.c = 12

Area without the top:

Area = ab + 2bc + 2ac

Cost  = 12ab + 8.2bc + 8.2ac

Cost = 12ab + 16bc + 16ac

height = 3.width

c = 3b

Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab

abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²

Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b

C(b) = 48b² + 240/b

C'(b) = 96b - 240/b²

Minimum cost: C'(b) = 0

96b - 240/b² = 0

(96b³ - 240)/b² = 0

96b³ - 240 = 0

96b³ = 240

b³ = 240/96

b³ = 2.5

b = 1.357m

c = 3b = 3*1.357 = 4.072m

a = 4/b² = 2.172m

6 0
3 years ago
3m/2/3=7 pleasee helpp​
snow_tiger [21]

Answer:

14

Step-by-step explanation:

3 times 14 equals 42, and 42 divided by 2 is 21. 21 divided by 3 is 7. :)

7 0
2 years ago
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