You need to covert the decimal to a fraction and then if they have the same denominator then compare by the numerator if they don’t the same denominator then change so they do have one then compare
Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
Answer:
the answer is x^12
Step-by-step explanation:
multiply 3 by 4 and you get 12
Answer:
5x+3y
Step-by-step explanation:
2x+3x=5x since they have the same variable.
y+2y
1y+2y u can put a 1 so that would be 3y
5x+3y
Answer:
14 minutes below or 6 minutes above
Step-by-step explanation:
Let's say Sophia's time was 10 minutes WORSE
4 minutes below average- 10 minutes= 14 minutes below average
Let's say Sophia's time was ten minutes BETTER
4 minutes below average + 10 minutes= 6 minutes above average.
Hope this helps!
