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Nina [5.8K]
3 years ago
13

An urn contains 3 red, 8 yellow and 13 green balls; another urn contains 5 red, 7 yellow and 6 green balls. We pick one ball fro

m each urn at random. Find the probability that both balls are of the same color.
Mathematics
1 answer:
kkurt [141]3 years ago
8 0

Answer:

The number of possible outcomes is 24×18.

The number of favorable outcomes are as follows: (3×5)+(8×7)+(13×6)

The probability is simply:

(3×5)+(8×7)+(13×6)/24×18=149/432

Step-by-step explanation:

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Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

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Then the number of combinations is

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Case 1 + case 2 = 324 + 2592 = 2916

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3 years ago
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