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3 years ago

Find the diameter of each circle.

Mathematics

2 answers:

sdas [7]3 years ago

4 0

7.8

They give you the radius, which is half the diameter.

3.9 * 2 = 7.8

Dahasolnce [82]3 years ago

4 0

answer:

1. 7.8 km

2. 17 ml

step-by-step explanation:

for the first one, we are given the radius
know that, the diameter is two times bigger than the radius
so, for both of these we have to multiply what is given by 2

1 — 3.9 X 2 = 7.8 km

2 — 8.5 X 2 = 17 mi

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In a class test(3+) marks are given for every correct answer and (-2) marks are given for every incorrect answer (-2) marks are

Diano4ka-milaya [45]

The number of incorrect answers made by Radhika is 8; the number of incorrect answers made by Mohini = 13

<h3>How to solve algebra word problems?</h3>

We are given;

Marks obtained for 1 right answer = +3

Marks obtained for 1 wrong answer = −2

(i) Marks scored by Radhika = 20

Marks obtained for 12 correct answers = 12 × 3 = 36

Marks obtained for incorrect answers = Total score − Marks obtained for 12 correct answers = 20 − 36 = −16

Marks obtained for 1 wrong answer = −2

Thus, number of incorrect answers = (−16) ÷(−2) = 8

Therefore, the number of incorrect answers made by Radhika = 8

(ii) Marks scored by Mohini = −5

Marks obtained for 7 correct answers = 7 × 3 = 21

Marks obtained for incorrect answers = Total score − Marks obtained for 12 correct answers = − 5 − 21 = −26

Marks obtained for 1 wrong answer = −2

Thus, number of incorrect answers = (−26) ÷ (−2) = 13

So, the number of incorrect answers made by Mohini = 13

Read more about Algebra word problems at; brainly.com/question/21405634

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3 0

2 years ago

Iff (x) = 3x + 2 and g(x) = x? – x, find the value.<br> =<br> f (4)

earnstyle [38]

-4

I hope this helps (:

5 0

3 years ago

assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28

melomori [17]

Given:

x and y are both differentiable functions of t.

$4x^2+3y^3=28$

$x=-1\text{ and }\dfrac{dy}{dt}=8$

To find:

The value of $\dfrac{dx}{dt}$ .

Solution:

We have,

$4x^2+3y^3=28$ ...(i)

At x=-1,

$4(-1)^2+3y^3=28$

$4+3y^3=28$

$3y^3=28-4$

$3y^3=24$

Divide both sides by 3.

$y^3=8$

Taking cube root on both sides.

$y=2$

So, y=2 at x=-1.

Differentiate (i) with respect to t.

$4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0$

Putting x=-1, y=2 and $\dfrac{dy}{dt}=8$ , we get

$4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0$

$-8\dfrac{dx}{dt}+9(4)(8)=0$

$-8(\dfrac{dx}{dt}-9(4))=0$

Divide both sides by -8.

$\dfrac{dx}{dt}-36=0$

$\dfrac{dx}{dt}=36$

Therefore, the value of $4x^2+3y^3=28$ is 36.

6 0

3 years ago

Johnny uses 2-inch square tile to make a square, as shown below. What is the perimeter of Johnny's square? there are 3 2-inch ti

Monica [59]

So,

If we visualize it, we can see a 3 x 3 square, with each unit representing 2 in.

If we do simple multiplication, we can figure out that each side is 6 in. long.

Fourfold of 6 in. reveals the perimeter: 24 in.

4 0

4 years ago

Solve for x.<br> (17x - 23)<br> (&r - 4)*<br> -(3x + 17)

Finger [1]

Answer:

17rx2−23rx−71x+75

Step-by-step explanation:

(17x−23)(xr−4)−(3x+17)

=(17x−23)(xr−4)+−1(3x+17)

=(17x−23)(xr−4)+−1(3x)+(−1)(17)

=(17x−23)(xr−4)+−3x+−17

=(17x)(xr)+(17x)(−4)+(−23)(xr)+(−23)(−4)+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=(17rx2)+(−23rx)+(−68x+−3x)+(92+−17)

=17rx2+−23rx+−71x+75

6 0

3 years ago