Question

1/sin10°-√3/cos10°=4​

Answer 1

Answer:

$\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=4$

Step-by-step explanation:

Given the expression

$\frac{1}{\sin \left(10^{\circ \:}\right)}-\frac{\sqrt{3}}{\cos \left(10^{\circ \:}\right)}=4$

Taking the left-hand side and solving it

$\frac{1}{\sin \left(10^{\circ \:}\right)}-\frac{\sqrt{3}}{\cos \left(10^{\circ \:}\right)}$

as

$\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=5.76$

and

$\frac{\sqrt{3}}{\cos \left(10^{\circ \:\:}\right)}=1.76$

so the expression becomes

$\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=5.76-1.76$

                           $=4$

Thus, we conclude that

$\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=4$