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castortr0y [4]
3 years ago
13

Help po plssssssssss need na po kasi ASAP

Mathematics
1 answer:
Blababa [14]3 years ago
4 0

Answer:

I will help you what question

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If ∠x= 55, then find the values of a, b, c and d
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The sum of two numbers is 21. the second number is six times the first number . Work out the two numbers
jeyben [28]

Answer:

3 and 6

Step-by-step explanation:

3*6=18

18+3=21

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For every four female students in a training class, there are two men. What the ratio of female to male students
grandymaker [24]
The ratio is 4 to 2
Hope this helps
6 0
3 years ago
Read 2 more answers
Use the graph to complete the statement. O is the origin. Ry−axis ο Ry=x: (2,3) A. (-2, -3) B. (3, -2) C. (2, -3) D. (-3, 2)
horrorfan [7]

Answer:

D

Step-by-step explanation:

Given

R_{y-axis} ○ R_{y=x} : (2, 3 )

Then the order of reflections is from right to left, that is

Under a reflection in the line y = x

a point (x, y ) → (y, x ) , thus

(2, 3 ) → (3, 2 )

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , thus

(3, 2 ) → (- 3, 2 ) → D

3 0
4 years ago
A genetic experiment with peas resulted in one sample of offspring that consisted of 438 green peas and 173 yellow peas.
Andre45 [30]

Answer:

a

The 95% confidence interval is 0.2474 < p < 0.3188

b

  The result obtained does not contradict expectation

Step-by-step explanation:

From the question we are told that

   The number of green peas is  k =  438

   The number of yellow peas is u =  173

Generally the sample size is mathematically represented as

       n  =  k + u

=>    n  = 438 + 173

=>    n  = 611

Generally the sample proportion for yellow peas is

      \^ p = \frac{u}{n}

=>   \^ p = \frac{173}{611 }

=>   \^ p = 0.2831

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>  E =  1.96 * \sqrt{\frac{ 0.2831 (1- 0.2831)}{611} }

=>  E =  0.0357

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>     0.2831  -0.0357

=>     0.2474 < p < 0.3188

From the question we are told that it was expected that 25% of the offspring peas will be yellow

   Now from the 95% confidence interval obtained we see that the expected sample proportion(25% ) falls within it so  it means that the result obtained does not contradict expectation

7 0
3 years ago
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