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amid [387]
3 years ago
13

Dimitrius returned 5 library books last week, returned 3 books this week, and then checked out 8 more books. He now has 12 libra

ry books. How many books did he have before last week?
Mathematics
2 answers:
g100num [7]3 years ago
8 0
To solve this problem, we have to set up an equation. Let the variable x represent the number of books that Dimitrius had before last week. x - 5 - 3 + 8 = 12 To begin simplifying this equation, lets combine terms on the left side of the equation. x - 8 + 8 = 12 The -8 and +8 cancel each other out, leaving us with: x=12 Therefore, Dimitrius had 12 books before last week. Hope this helps! :)
Arte-miy333 [17]3 years ago
7 0

Answer:

He had 12 books

Step-by-step explanation:

Let x be the number of books he had before last week,

After returning 5 books, remaining books = x - 5,

Again after returning 3 more books, remaining books = x - 5 - 3 = x - 8

After checking out 8 more books,

Final number of books = x - 8 + 8 = x

According to the question,

Final number of books = 12,

⇒ x = 12

Hence, he had 12 books before last week.

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If one root of the equation is 4x^2- 2x+p-4 be the reciprocal of other. then find the value of p​
SashulF [63]

Answer:

p = 8

Step-by-step explanation:

Let one root of the eqn. be alpha . Other root is 1/alpha .

We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant  & "a" is the co-efficient of x^2.

Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )

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5 0
4 years ago
The triangles below are similar. Triangle A B C. Side A C is 10 and side A B is 5. Angle C is 30 degrees. Triangle D E F. Side E
Gnoma [55]

Answer:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

Step-by-step explanation:

Given

\triangle ABC {\displaystyle \sim } \triangle DE\ F

AC = 10

AB = 5

\angle C = 30^\circ

ED = 7.5

DF = 25

\angle F =30

\angle E =90

Required

Which of the options is/are true:

\triangle CBA {\displaystyle \sim } \triangle FED            \triangle CBA {\displaystyle \sim } \triangle FDE              \triangle BAC {\displaystyle \sim } \triangle EFD

\triangle BAC {\displaystyle \sim } \triangle EDF            \triangle ABC {\displaystyle \sim } \triangle DE\ F             \triangle ABC {\displaystyle \sim } \triangle DFE

The given triangles, implies that:

A {\displaystyle \sim } \ D

B {\displaystyle \sim } \ E

C {\displaystyle \sim } \ F

By taking each sides of both triangle, one after the other; the possible similar triangles are:

\triangle ABC {\displaystyle \sim } \triangle DE\ F

\triangle CBA {\displaystyle \sim } \triangle FED

\triangle BAC {\displaystyle \sim } \triangle EDF

5 0
3 years ago
Anyone know the answer???
alisha [4.7K]

Hello from MrBillDoesMath!

Answer:

k = 10

Discussion:

angle MYK = 180 and angle MYX = 180 =>  angle ZYX = 180 - 115 - 65

Trialing XYZ has 180 degrees so

180 =  (4k + 5) +  (6k+10) + 65     => combine like terms

180 = (4k + 6k) + (5 + 10 + 65)     => as 4k +6k = 10k

180 = 10k  + 80                              => subtract 80 from both sides

180 -80 = 100 = 10k                      => divide both sides by 10

100/10 = k

Thank you,

MrB

5 0
4 years ago
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