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3 years ago

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3.26d+9.75d-2.65 please help

1 answer:

Paha777 [63]3 years ago

5 0

Answer:

okay so what you do is you start by addinf 3.26d to 9.75d which gets you 13.01d

Step-by-step explanation:

the answer would be 13.01d-2.65

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The base of a regular pyramid is a hexagon

Readme [11.4K]

Answer:

Below in bold.

Step-by-step explanation:

The hexagon is made up of 6 equilateral triangles.

So the Base = 12 cm.

Height a = 12 cos 30 = 10.392 cm

So area of 1 triangle = 1/2 * 12 * 10.392 cm^2

- and total area = 6 * 1/2 * 12 * 10.392

= 36 * 10.392

= 374.11 cm^2 to the nearest hundredth.

7 0

2 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

Write an equation of the line that passes through (-4, -6) and is parallel to y= 3x - 8

Irina18 [472]

The equation is 3×-2y= -16

6 0

3 years ago

There are 33.8 fluid ounces in a liter. There are 128 fluid ounces in a gallon. About how many liters are in a gallon? *

Tamiku [17]

Answer:

A

Step-by-step explanation:

three liters in a gallon

3 0

3 years ago

Read 2 more answers

graph the function n(x) = (x-1)^2 -7. compare the graph to the graph of f(x) = x^2. i have the vertex which is (-1,-7) how do I

bogdanovich [222]

Answer:

See below.

Step-by-step explanation:

To find the other two points such as the x-intercepts, set the equation equal to 0 and solve for x.

$0 = (x-1)^2 -7\\\\7 = (x-1)^2\\\\\sqrt{7} = \sqrt{(x-1)^2} \\\\+/-\sqrt{7} = (x-1)\\1+/-\sqrt{7} = x$

This means the points will be at (3.64, 0) and (-1.64, 0).

This graph is shifted 1 unit to the right and 7 units down from x^2.

5 0

3 years ago