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3 years ago

PLZ HELP 35 points ill award brainliest

Mathematics

1 answer:

madreJ [45]3 years ago

6 0

Step-by-step explanation:

You will get the distance each ran by multiplying the speed each ran at and the time taken, and add the two results.

the distance puppy ran in 15 seconds= 6×15=90 meters

the speed of the kitten=2/3×6=4 meters per second

the distance the kitten ran in 15 seconds=4×15=60 meters

So, the total distance is 90+60=150 meters.

(Alternate method)

Since the two ran in opposite directions, you can add the running speeds of the two and multiply it with time.

(4+6)×15=150 meters

Note: If they ran in the same direction, you would have to find the difference between their running speeds and multiply it with time taken.

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A boat traveled 153 miles downstream and back. The trip downstream took 9 hours. The trip back took 17 hours. What is the speed

fgiga [73]

Speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour

<h3>Solution:</h3>

Let s = the speed of the boat in still water in miles/hour

Let c = the speed of the current in miles/hour

Formula to remember:

If the speed of a boat in still water is s miles/hr and the speed of the current is c miles/hr, then:

Speed downstream = (s + c) miles per hour

Speed upstream = (s - c) miles per hour

Given:

boat traveled 153 miles downstream and back

distance for downstream = 153 miles

distance for upstream = 153 miles

time taken for downstream = 9 hours

Time taken for upstream = 17 hours

The relation between speed, distance and time is given as:

$distance = speed \times time$

For downstream:

$153 = (s + c) \times 9$

$s + c = \frac{153}{9} = 17$

s + c = 17 ------- eqn 1

For upstream:

$153 = (s - c) \times 17\\\\s - c = \frac{153}{17} = 9$

s - c = 9 ------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "s" and "c"

Add eqn 1 and eqn 2

s + c = 17

s - c = 9

(+) -------------

2s = 26

Substitute s = 13 in eqn 1

13 + c = 17

c = 17 - 13 = 4

Thus the speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour

8 0

3 years ago

Find the length of the mid segment (median)

velikii [3]

Answer:

Step-by-step explanation:

Median of a trapezoid = sum of 2 bases divided by 2

Bases = 10 and 16

Median = (10 + 16)/2

10 + 16 = 26

26/2 = 13

Median = 13

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3 years ago

The town indoor pool is in a rectangular building. Marco is laying tile

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Where is the rest you cut it off

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4 years ago

Mia ran around 0.10 of the school track. Sam ran around 0.5 of the playground. Sam says he ran farther. With the information giv

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Is there anymore info given?

6 0

3 years ago

The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the op

andreev551 [17]

B) $x =4.28$

C) volume = $135.25cm^3$ .

Step-by-step explanation:

Here we have , The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the open box is (x-2) cm. We need to find the following :

a) show that 2x^2+5x-58=0

We know that area of rectangle = $length(width)$

⇒ $Area = length(width)$

Putting values according to question we get :

⇒ $58 = (2x+5)(x)$

⇒ $58 = (2x^2+5x)$

⇒ $2x^2+5x - 58 = 0$

b) solve the equation in the question above, giving your answer to 2 decimal places

Solving this equation :

⇒ $2x^2+5x - 58 = 0$

By quadratic formula

⇒ $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $x = \frac{-5 \pm \sqrt{5^2-4(2)(-58)} }{2(2)}$

⇒ $x = \frac{-5 \pm 22.11}{4}$

⇒ $x = \frac{-5 + 22.11}{4} , x = \frac{-5 - 22.11}{4}$ { Since side can't be negative ! }

⇒ $x =4.28$

c) calculate the volume of the box, stating units of you answer

Since x = 4.28 , other sides are

$2x+5=2(4.28)+5=13.56\\x-2=4.28-2=2.28$

We know that volume is given by :

⇒ $length(width)(height)$

⇒ $13.86(4.28)(2.28)$

⇒ $135.25cm^3$

Therefore , volume = $135.25cm^3$ .

7 0

3 years ago