Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is

8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute
P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)
(since P(<em>X</em> > 10) = 0)
… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)
… = 0.2055
Answer:
y = (N/24)x
Step-by-step explanation:
Let N be the no. of announcements per day (in 24 hours)
N/24 per hour
y = (N/24)x
Answer:
7 answer is 4+2√129 I think
First you need to distribute. when you do this you get (8v+8w)-(7v+14w) then you get like terms together, but don't forget that everything in (7v+14w) is negative. when you group like terms together you get (8v-7v)+(8w-14w) simplify and you get v-6w