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3 years ago

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Mathematics

1 answer:

Ber [7]3 years ago

7 0

use m a t h w a y for all your needs

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what would be an outlier if added to the data set below? 507, 586, 499, 542, 615, 600, 561, 519 A.487 B.535 C.610 D.380

Trava [24]

I am pretty sure the answer is F

5 0

4 years ago

What is the determinant of the matrix [598−2]

mihalych1998 [28]

Answer:

-82

Step-by-step explanation:

Maybe you want the determinant of ...

$\left[\begin{array}{cc}5&9\\8&-2\end{array}\right]$

The determinant of a 2×2 matrix is the difference of the products of elements on the down diagonal and the up diagonal:

D = (5)(-2) -(8)(9) = -10 -72 = -82

The determinant of this matrix is -82.

5 0

3 years ago

2/3 (x + 7) = 10 A) 22 B) 8 C)- 1 3 D 41 3 help me quick plz

otez555 [7]

Answer:

Step-by-step explanation:

D BECAUSE IT IS D

4 0

3 years ago

What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y = 27 − x^2? show your

LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given curve is

$y=27-x^2$

We need to find the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve $y=27-x^2$ .

Let the vertex in quadrant I be (x,y), then the vertex in quadrant II is (-x,y) .

Length of the rectangle = 2x

Width of the rectangle = y

Area of a rectangle is

$Area=Length\times width$

$Area=2x\times y$

Substitute the value of y from the given equation.

$Area=2x(27-x^2)$

$A=54x-2x^3$ .... (1)

Differentiate with respect to x.

$\frac{dA}{dx}=54-6x^2$

Equate $\frac{dA}{dx}=0$ , to find the critical points.

$0=54-6x^2$

$6x^2=54$

Divide both sides by 6.

$x^2=9$

$x=\pm 3$

The value of x can not be negative because side length can not be negative.

Substitute x=3 in equation (1).

$A=54(3)-2(3)^3$

$A=162-54$

$A=108$

The area of the largest rectangle is 108 square units.

Therefore, the correct option is B.

7 0

3 years ago

√-225 • √-36 . show work.

Darya [45]

Answer:

±90

Step-by-step explanation:

√(-225) · √(-36) = (15i)·(6i) = 90i² = 90·(-1) = -90

_____

On the other hand, ...

... √(-225) · √(-36) = √((-225)·(-36)) = √8100 = 90

___

If you consider all the roots at each stage, the result is ±90. Since you're working with complex numbers here, it is reasonable to recognize every number has two square roots.

... √(-225) = ±15i

... √(-36) = ±6i

... √(-225) · √(-36) = (±15i)·(±6i) = ±90i² = ±90

7 0

3 years ago