Answer:
S= z (y-x)/(x+y)
Step-by-step explanation:
Lets the speed of high speed train = u
Lets the regular speed train = v
We know that
Distance = Speed x time
For high speed train
z = u .x
u= z/x ----------1
For regular speed train
z = v .y
v = z/y -------------2
Both are traveling in opposite direction so relative speed
Vr = z / x+ z /y
Lets in time t they will meet
z = (z / x+ z /y) t
t= xy/ (x+y)
Lets take distance cover by high speed train is m when it moves A to B and speed cover by regular train is n when it is moving B to A.They meet at time t.
m = u .t
m = z / x .xy/ (x+y)
m = zy/ (x+y) -----------3
n = v .t
n = z / y .xy/ (x+y)
n = zx/ (x+y) -----------4
From equation 3 and 4
So
m - n= zy/ (x+y) - zx/ (x+y)
S= z (y-x)/(x+y)
Option a is correct.
Answer:
the volume at 606k is 2.22....the third one
Step-by-step explanation:
v1=1.00 t1=273 v2=? t2=606
v1/t1=v2/t2
1.00/273=v2/606
1.00×606=273v2
606=273v2
606/273=v2
2.21 L=v2
Answer:
12.D
13.C
14.A
15.B
16.A
17.B
18.D
19.A
20.A
and hey I don't know the answer to 11 th question as I don't know much about miles
PS: Have a nice day :)
Answer:
is the answer to that question d?
The answer is 6x^2 - 8x + 2
