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Savatey [412]
3 years ago
11

The least total cost method (LTC) lot-sizing technique calculates the order quantity by comparing the carrying cost and the setu

p (or ordering) costs for various lot sizes and then selects the lot in which these are most nearly equal. Group of answer choices True False
Mathematics
1 answer:
rewona [7]3 years ago
8 0

Answer:

True

Step-by-step explanation:

The least total cost method is the method in which the total cost of the ordering cost and the total carrying cost is equal among various lot size available.

The order quantity should be choose when the total ordering cost and the total carrying cost equal to each other

The formula to compute the economic order quantity is shown below:

a. The computation of the economic order quantity is shown below:

= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}

It is always be expressed in units

The formula to compute the ordering cost is

= \frac{Annual\ demand}{Economic\ order\ quantity}\times ordering\ cost\ per\ order

And, the formula to compute the carrying cost is

= \frac{Economic\ order\ quanity}{2}\times carrying\ cost\ per\ unit

Hence, the given statement is true

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The density of mercury is 13.6 grams per cubic centimeter. Complete the steps for converting 13.6 g/cm^3 to kg/m^3
Mama L [17]

1 cubic meter = 100 cm * 100 cm * 100 cm = 1 x 10^6 cc

1 kilogram = 1,000 grams

13.6 g / cc

If we had a cubic meter of mercury, its mass would be (or it would "weigh") 13.6 * 1,000,000 = 13,600,000 grams or 13,600 kilograms.

And so its density would be 13,600 kg / cubic meter.


4 0
3 years ago
Please help me with number six
Tpy6a [65]

w = 2x = 2( \frac{y}{3}) \\ v = 2w = 2 \times 2( \frac{y}{3} ) \\ v + w  + x + y = 180 \\  \frac{4}{3} y +  \frac{2}{3} y +  \frac{y}{3}  + y = 180 \\ y( \frac{4}{3}  +  \frac{2}{3}  +  \frac{1}{3}  + 1) = 180 \\ y =  \frac{180}{()}
5 0
3 years ago
6x + 3y = 33 4x + y = 15 A. x = 2, y = 7 B. x = -13, y = 7 C. x = - 2 3 , y = 12 2 3 D. x = 5, y = 1
klio [65]

6x+3y=33..........(1)

4x+y=15

y=15-4x.........(2)

substitute value of y from (2) in (1)

6x+3(15-4x)=33

distribute 3 over the bracket

6x+45-12x =33

-6x=33-45

-6x=-12

x=2

plugging this value of x in equation 2 we get

15-4x=y

15-4(2)=y

y=15-8

y=7

Answer is x=2 and y=7

3 0
3 years ago
If the diameter of circle O is 20 and CE = 4, then determine the length of AB. Show how you arrived at your answer.
Aneli [31]

Answer:  Length of AB is 16 cm

Step-by-step explanation:

Given: Diameter of a circle is 20 cm and CE = 4 cm

Now as shown in figure AO, BO, CO are radii

\text { Radius } =\dfrac{\text {Diameter}}{2} = \dfrac{20}{2} = 10 cm

Therefore

AO=BO=CO= 10 cm

Now

OE = CO- CE  \Rightarrow OE= 10 -4 = 6 cm

Now in Δ OEB

∠OEB =90°

Therefore by Pythagoras theorem : In a right angle triangle the square of hypotenuse is equal to the sum of square of other two sides.

So we have

BO^2=BE^2+EO^2\\\\\Rightarrow 10^2= BE^2 +6^2\\\\\Rightarrow BE^2= 100-36\\\\\Rightarrow BE^2 = 64 \\\\\Rightarrow BE= 8 cm

Now as we know perpendicular to the chord from the center of a circle bisect the chord.

Therefore

AB= 2\times BE = 2\times 8=16 cm

Hence , the  length of AB is 16 cm .

8 0
3 years ago
Graph the first six terms of a sequence where a1 = −10 and d = 3. (2 points)
liberstina [14]
It will be a1 times D

4 0
3 years ago
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