1 cubic meter = 100 cm * 100 cm * 100 cm = 1 x 10^6 cc
1 kilogram = 1,000 grams
13.6 g / cc
If we had a cubic meter of mercury, its mass would be (or it would "weigh") 13.6 * 1,000,000 = 13,600,000 grams or 13,600 kilograms.
And so its density would be 13,600 kg / cubic meter.
6x+3y=33..........(1)
4x+y=15
y=15-4x.........(2)
substitute value of y from (2) in (1)
6x+3(15-4x)=33
distribute 3 over the bracket
6x+45-12x =33
-6x=33-45
-6x=-12
x=2
plugging this value of x in equation 2 we get
15-4x=y
15-4(2)=y
y=15-8
y=7
Answer is x=2 and y=7
Answer: Length of AB is 16 cm
Step-by-step explanation:
Given: Diameter of a circle is 20 cm and CE = 4 cm
Now as shown in figure AO, BO, CO are radii

Therefore
AO=BO=CO= 10 cm
Now

Now in Δ OEB
∠OEB =90°
Therefore by Pythagoras theorem : In a right angle triangle the square of hypotenuse is equal to the sum of square of other two sides.
So we have

Now as we know perpendicular to the chord from the center of a circle bisect the chord.
Therefore

Hence , the length of AB is 16 cm .