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3 years ago

Plsss help me no linkss

Mathematics

1 answer:

Luda [366]3 years ago

3 0

<h2>Figure 1: Pyramid.</h2>

Area of the Base: 96

Formula for Base Area: A = L × W

Volume: 640

Formula for Pyramid volume: $\frac{L\times W\times H}{3}$

<h2>Figure 2: Triangular Prism</h2>

Area of Base: 80

Formula for Base Area: 1/2 × base side × height

Volume: 960

Formula: 1/2 × B × L × H

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Let us take as a given that x is normally distributed with a mean of 8.5 and a standard deviation of 2, what is p(x ≤ 6)? note:

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Please help!

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Answer:

$\sf C. \quad \dfrac{1}{9}$

Step-by-step explanation:

<u>Addition Law for Probability</u>

$\sf P(A \cup B)=P(A)+P(B)-P(A \cap B)$

Given:

$\sf P(A)=\dfrac{1}{3}=\dfrac{3}{9}$

$\sf P(B)=\dfrac{2}{9}$

$\sf P(A \cup B)=\dfrac{4}{9}$

Substitute the given values into the formula and solve for P(A ∩ B):

$\implies \sf P(A \cup B) = P(A)+P(B)-P(A \cap B)$

$\implies \sf \dfrac{4}{9} = \sf \dfrac{3}{9}+\dfrac{2}{9}-P(A \cap B)$

$\implies \sf P(A \cap B) = \sf \dfrac{3}{9}+\dfrac{2}{9}-\dfrac{4}{9}$

$\implies \sf P(A \cap B) = \sf \dfrac{3+2-4}{9}$

$\implies \sf P(A \cap B) = \sf \dfrac{1}{9}$

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