Answer:
Step-by-step explanation:
This should help I hope
<h3>Answer:</h3>
B) 10 pounds
<h3>Explanation:</h3>
Let x represent the amount of 70¢ candy to be added. The value of the mixture can be written as ...
... 90×30 + 70x = 85×(30+x) . . . . . where 30+x is the total weight of the mix
... 2700 +70x = 2550 +85x
... 150 = 15x . . . . . . add -70x-2550
... 10 = x . . . . . . . . . divide by the coefficient of x
10 pounds of candy at 70¢/lb must be added.
Answer:
commutative propriety of addition
Step-by-step explanation:
M+P =P+M is an example of the commutative propriety of addition
when numbers or parentheses connected by addition or multiplication switch places (commute) we have commutative propriety of addition or multiplication
Step One
======
Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
A is true--------------------------
