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3 years ago

How much is 79tens plus 10 tens in standard form

Mathematics

2 answers:

IrinaVladis [17]3 years ago

6 0

Is it 79 sets of ten or 79 tenths

Ahat [919]3 years ago

3 0

I think it is 89 tenths since it says 79 tenths and 10 tenths

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The height of a stack of 12 pennies is 18.24 millimeters. What is the thickness of each penny.

Helga [31]

I’m not great at math so I could easily be wrong, but

I divided the 18.24 millimeters by 12 pennies and got 1.52

So if the pennies are all the same size, each penny should 1.52 millimeters.

To show work:

18.24/12=1.52

4 0

3 years ago

Why are bars of the histogram all the same width?

Aleksandr-060686 [28]

The widths of the bars are equal to ensure that numbers aren't represented improperly. If a bar was wider than another that was the same height, it could be misinterpreted as being larger.

3 0

3 years ago

Thank you very much for your help!

Kobotan [32]

For a.
$x^2+y^2=25$

For b.
$(x-4)^2+(y-3)^2=25$

For c.
$(x-5)^2+(y-4)^2=9$

Hope that helps

5 0

3 years ago

A researcher wants to test whether a certain sound will make rats do worse on learning tasks. It is known that an ordinary rat c

AveGali [126]

Answer:

So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.

Step-by-step explanation:

In this data we have

Mean= u = 18

X= 38

Standard deviation = s= 6

1) We formulate the null and alternate hypothesis as

H0: u = 18 against Ha : u > 18 One tailed test .

2) The significance level alpha = ∝= 0.05 and Z alpha has a value ± 1.645 for one tailed test.

3)The test statistics used is

Z= X- u / s

z= 38-18/6= 3.333

4) The calculated value of z = 3.33 is greater than the z∝ = 1.645

5) So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.

First we set the criteria for determining the true of value of the variable. That whether the rats learn in less or more than 18 trials.

Then we find the value of z for the given significance value given and the test about to be checked.

Then the test statistic is determined and calculated.

Then both value of z and z alpha re compared. If the test statistics falls in the rejection region reject the null hypothesis and conclude alternate hypothesis is true.

The figure shows that the calulated z value lies outside the given z values

4 0

3 years ago

I NEED HELP FAST!!!!!!!!!! ⦁ Solve the equation. Describe the solution to the equation as one solution, no solution, or an infin

g100num [7]

$\frac{1}{8} (x + 24) = \frac{5}{8} x + 9 - \frac{1}{2} x \\ \\ \frac{x + 24}{8} = \frac{5}{8} x + 9 - \frac{1}{2} x \ / \ simplify \\ \\ \frac{x + 24}{8} = \frac{5x}{8} + 9 - \frac{1}{2} x \ / \ simplify \\ \\ \frac{x+ 24}{8} = \frac{5x}{8} + 9 - \frac{x}{2} \ / \ simplify \\ \\ \frac{x + 24}{8} = \frac{x}{8} + 9 \ / \ simplify \\ \\ x + 24 = x + 72 \ / \ multiply \ each \ side \ by \ 8 \\ \\ 24 = 72 \ / \ cancel \ x \\ \\ no \ solution \\ \\$

The final result is: no solution.

7 0

3 years ago

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