The answer is 16
4+4+4+4=16
OK so here it goes:
1a. 10³
1b. 10²
1c. 10(tiny 6)
1d. 10³
1e. 10(tiny6)
1f. 10(tiny 5)
2a. 400
2b. 640,000
2c. 5,400
2d. 5,301,000
2e. is it multipcation or addition
2f. 607,200
2g. 0.948
2h. 0.0094
3a) 0.02, 0.2, 2, 20, 200, 2000
3b) 3,400,000 ; 34,000; 340, 3.4, 0.034
3c) 85,700; 8,570; 857, 85.7, 8.57, 0.857
3d) 444, 4440, 44,400; 440,000; 4,400,000; 44,000,000
3e) 0.95, 9.5, 950, 95,000; 950,000; 9,500,000
Hope this helps.
Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
Answer:
maximum 4 Mimimum I'm 0 or maximum 10 minimum 0
