Answer:
This should be parallel.
Step-by-step explanation:
Two lines are said to be parallel only if their slope matches. They are said to be perpendicular only if the slopes are negative reciprocals.
Here, you should put both equations in slope intercept form which is y=mx+b. The letter "M" represents the slope of both equations.
2y-6=3x+4 turns into 2y=3x+10 after adding 6 and into y=3/2x+5 after dividing the equation by 2. The slope for this equation is 3/2.
8y=12x+8 must be divided by 8 to be in slope intercept form. This equation becomes y=3/2x+1. Here the slope is also 3/2.
The slopes for each equation match making these lines parallel.
Option D is the correct answer.
Step-by-step explanation:
Step 1 :
Let A represent the cost of one bucket of apple and P represent the cost of one bucket of peaches.
So we have ,
4 buckets of apples and 5 buckets of peaches for $64
8 buckets of apples and 3 buckets of peaches for $72
Writing this in the equation form we have,
4A + 5P = 64
8A + 3P = 72
Step 2:
Solving for the above 2 equations we can get the required costs
Equation 1 is
4A + 5P = 64 , Multiplying this by 2 we have 8A + 10P = 128
Equation 2 = 8A + 3P = 72
Subtracting both we have , 7p = 56 = > P = 8
Substituting this in equation 1 we have
8A + 80 = 128 => A = 6
Hence the cost of one bucket of apple is $6 and the cost of one bucket of apple is $8.
Option D is the correct answer.
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The diagram is missing but I'll assume that the arc BDC is:
And another arc, let's call it FGH. measures:
If those arc are equal, then this equation is true:
Substituting k into the first equation:
Is the same as the one you just did.
keep in mind that, going against the current, the current's speed erodes speed from your regular speed, whilst if you're going with the current, the current's speed adds to it.
now, in this case, you row 5mph, going upstream you're only doing 3mph, whatever happened to the other 2mph? well, the current speed eroded them, meaning the speed of the river is 2mph.
now, going downstream with the current, your regular speed is 5mph, and the current is 2mph, since the current adds to yours, then you're going 5 + 2, mph.
Complementary I’m sure but I could be wrong
