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iragen [17]
3 years ago
6

Please help meif don't know don't answer, if you answer i will report ​

Mathematics
2 answers:
dedylja [7]3 years ago
5 0

Answer:

(a)=

4(m+3)=18

4m+12=18

4m=18-12

4m=6

m=

\frac{6}{4}

(b)=

-2(p+5)+8=0

-2p-10+8=0

-2p=0+10-8

-2p=2

p=

\frac{2}{ - 2}  =  - 1

(c)=

3+5(t-1)=8

3+5t-5=8

5t=8-3+5

5t=10

t=

\frac{10}{5}  = 2

please \: mark \: as \: brainliest \: because \: i \: spent \: much \: time \: on \: this \: question

Amanda [17]3 years ago
4 0

Answer:

A.) m = 1.5 | B.) p = -1 | C.) t = 2

Step-by-step explanation:

A.)

4(m+3)=18\\4m+12=18\\4m=6\\m=3/2=1.5

B.)

-2(p+5)+8=0\\-2p-10+8=0\\-2p-2=0\\-2p=2\\p=-1

C.)

3+5(t-1)=8\\3+5t-5=8\\5t-2=8\\5t=10\\t=2

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9x+18+3x=1
Katen [24]
The error is in the second step they subtracted 3 from both sides but it was a 3x, which you can not do.
Correction.
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3 years ago
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Which of the following sets contain all roots of the polynomial
Zarrin [17]

All these given roots are contained in option C.

The given equation is :

9x^{3}+9x^{2}-4x-4=0

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3 years ago
A 1L IV contains 60meq of kcal. The IV was discontinued after 400ml has infused. How much lvl did the patient receive
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If a 1L IV contains 60meq of kcal and the IV was discontinued after 400ml has infused, then the amount of IV received by the patient is 24meq of kcal.

Calculation for the Amount of IV

It is given that,

1L IV contains 60meq of kcal

⇒ 1000 mL of IV contains 60meq of kcal

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As per the question,

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Answer:

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