Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
There are infinite numbers
Answer:
I'm confused by the points:
Why three points for each (A, B, C, and D)?: A: (0,6)(0,6)(0,6), etc.
Points A and B [(0,6) and (4,2)] are consistant with a straight line of the form y=-x+6.
Points C and D [(-6,8),(-8,10)]are on the line y=-x+2.
A and B aren't related to C and D.
Step-by-step explanation:
Question 1. It is graph 3 since the y-intercept in the equation is -2 and the y-intercept on the graph 3 is -2. It is also a quadratic function.
Question 2. It is graph two because the equation listed represents a quadratic function that is positive (graph opens up).
Question 3. It is graph 4 since the y-intercept is 2 and the only graph with that intercept is graph 4. Also, the equation represents a linear function.
Hope this helped :))
