Question

Find the height in centimeters of a square pyramid with a volume of 455cm3 and a base edge length equal to the height. Give the approximate answer rounded to 2 decimal places.

Answer 1

Answer:

$h = 7.69cm$

Step-by-step explanation:

Given

$Volume = 455cm^3$

$l = h$

Where:

$h \to height$

$l \to base\ length$

Required

The height

The volume is calculated as:

$Volume = l^2 * h$

This gives:

$Volume = h^2 * h$

$Volume = h^3$

Rewrite as:

$h^3 =Volume$

So, we have:

$h^3 = 455cm^3$

Take cube roots

$h = \sqrt[3]{455cm^3}$

$h = 7.69cm$ --- approximated