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3 years ago

In a week, 20 hens laid 60 eggs. What is the unit rate for eggs per hen?

Mathematics

1 answer:

Serggg [28]3 years ago

5 0

That’s a fat 100 girls

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Round 0.173 to the nearest hundredth

Montano1993 [528]

0.173 to the nearest hundredth would be 0.17
Hoped this helped!

8 0

3 years ago

Read 2 more answers

What is tan(x)-5=0<br> (With steps)

sp2606 [1]

Tanx-5=0
tanx=5
tan inverse (5)=x
78.69

7 0

3 years ago

PLS HELP ME FAST PLS !!!!!!!!!!!

erastova [34]

Answer:

The Answer is P = (-2.5 , 1 )

Step-by-step explanation:

Let, the point is P(x,y)

then, $x=\frac{m_{1}x_{2}+ m_{2}x_{1}}{m_{1}+m_{2}}$

=> $x=\frac{5*(-1)+ 3*(-5)}{5+3}$

∴ $x=-2.5$

Again, $y=\frac{m_{1}y_{2}+ m_{2}y_{1}}{m_{1}+m_{2}}$

=> $y=\frac{5*7+ 3*(-9)}{5+3}$

∴ $y=1$

Thus, P = (-2.5 , 1 )

6 0

2 years ago

Eric's cell phone service costs $40.00 a month for unlimited calls. He also pays $0.02 for each text message he sends.

Kaylis [27]

Answer:

A. 40.021

Step-by-step explanation:

Unlimited calls = $40

Text message = $0.021

NOTE:There is a difference between the value you gave for cost of text messages in the question and the values given in the group of answers. I will use $0.021 for cost of text messages since it is common to all answer choices.

Total cost = Cost of unlimited calls + cost of text messages

C = $40 + $0.021

= $40.021

Therefore, the equation which represent the total cost in dollars for a month is 40.021

A. 40.021

4 0

3 years ago

Solve for x:a(a²+b²)x²+b²x-a

m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

$x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}$

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b² = (b² + 2a²)²

2. Solve for x

$\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}$

$\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}$

5 0

3 years ago