Step One
Begin by drawing a line parallel to the x axis. Create it so it goes through (0,1)
This line you have drawn should hit points on the figure at (-5,1) (-2,1) and (3,1)
You now have a figure on the bottom that is a trapezoid. It has 2 small triangles on top of it. We'll talk about them later.
Step Two
Find the area of the trapezoid.
<em>Formula</em>
Area = (b1 + b2)*h/2
h = 1 - - 3 = 4
b1 = 3 - - 8 = 11
b2 = 3 - - 5 = 8
Area = (11 + 8)*4 / 2
Area = (19 ) * 2
Area = 38
Step Three
Find the area of the small triangle on the left.
The base goes from -5 to - 2 which is 3 units.
The height goes from 1 to 3 (using the y axis as a reference) which is 2
Area = 1/2 * b * h
Area = 1/2 *3 * 2
Area = 3
Step Four
Find the area of the small triangle on the right.
The base is 5 (see if you can get 5 as an answer)
The height is 1.
Area = 1/2 b * h
Area = 1/2 5 * 1
Area = 2.5
Step Five
Total Area is found by adding the three areas together.
Total Area = trapezoid + small triangle on the left + small triangle on the right
Total Area = 38 + 3 + 2.5 = 43.5
43.5 <<<< answer
Answer:
B, 
Step-by-step explanation:
Using the law of cosines, which is 
, you can simply insert all the values.
c=|u+v|
a= r value of u (10)
b= r value of v (5)
To find C, you simply have to subtract v from u, and then subtract that number from 180 to find the reference angle.
I.E.: ∠135 - ∠30 = ∠105 ↔ 180 - 105 = 75 = C
so, the completed equation would be 10^{2} + 5^{2}- 2(10)(5)cos(75)
Not enough information. The question doesn't say how much one quart of paint covers.
EDIT: here's the solution
we have to find the total area of the 4 walls and subtract the area of the door. there are 2 walls with dimensions 16 by 10, and 2 walls with dimensions 16 by 12. so we have: 2(16*10)+2(16*12)=320+384=704 for the area of the walls. now, we can find the area of the door which is 3*8=24. <span>so we subtract the area of the door from the area of the walls, so we have: 704-24=680. </span><span>Since a quart of paint covers 100, then we divide and get 680/100=6.8 but since we need a whole number of quarts, we round up to get 7 quarts of paint. </span>
R2(<span>cos2</span>ϕ−<span>sin2</span>ϕ)−2rcosϕ=0<span><span>r2</span>(<span>cos2</span>ϕ−<span>sin2</span>ϕ)−2rcosϕ=0</span>
<span><span><span>r2</span>cos<span>(2ϕ)</span>−2rcosϕ=0</span><span><span>r2</span>cos<span>(2ϕ)</span>−2rcosϕ=<span>0
Now </span></span></span> divide through by <span><span>r≠0</span><span>r≠0</span></span>
and get
<span><span>rcos<span>2ϕ</span>−2cosϕ=0</span><span>rcos<span>2ϕ</span>−2cosϕ=0</span></span>
or
<span><span>r=2<span><span>cosϕ</span><span>cos<span>2ϕ</span></span></span></span><span>r=2<span><span>cosϕ</span><span>cos<span>2<span>ϕ</span></span></span></span></span></span>
