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miskamm [114]
2 years ago
13

If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?

Mathematics
1 answer:
Vladimir79 [104]2 years ago
5 0

Answer:

  x ≥ 1

Step-by-step explanation:

There are no domain restrictions on a(x), so we can find the domain of the composite function by looking at that composition:

  (b \circ a)(x)=b(a(x)) = b(3x+1)=\sqrt{(3x+1)-4}\\\\(b \circ a)(x)=\sqrt{3x-3}=\sqrt{3(x-1)}

The argument of the square root function must be non-negative, so we must have ...

  3(x -1) ≥ 0

  x -1 ≥ 0 . . . . . divide by 3

  x ≥ 1 . . . . . . . add 1

The domain of b(a(x)) is x ≥ 1.

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3 years ago
Help! I have solving systems of equations using substitution, and sometimes I have equations like this:
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For systems of equations try using graphing, substitution, and elimination. For example
{2x+7y=3}
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1) distribute -8y+7y=3
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so currently our solution is (0,-3)
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8 0
3 years ago
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5 0
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kakasveta [241]

Answer:

The answer in the attached figure

Step-by-step explanation:

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Using a graphing tool

see the attached figure

The answer in the attached figure

4 0
3 years ago
Read 2 more answers
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